PHP:将 64 位整数转换为字符串 [英] PHP: Converting a 64bit integer to string

问题描述

我正在尝试在字符串变量中使用硬编码的 64 位整数.

I'm trying to use a hardcoded 64bit integer in a string variable.

简化我想做这样的事情:

Simplfied I want to do something like this:

$i = 76561197961384956;
$s = "i = $i";

这应该导致 s 是:

i = 76561197961384956

这显然不起作用，因为 PHP 将大整数转换为浮点数，因此 s 是:

This does obviously not work as PHP cast big integers to float, therefore s is:

i = 7.65611979614E+16

虽然其他几种方法(如强制转换等)都失败了，但我找到了 number_format() 并像这样使用它:

While several other methods like casting etc. fail, I found number_format() and use it like this:

$s = "i = " . number_format($i, 0, '.', '');

但这导致 s 是:

i = 76561197961384960

看起来像是一个近似问题，但如何解决这个问题?

Looks like an approximation problem, but how to fix this?

推荐答案

您丢失了赋值的精度，而不是字符串转换的精度.如果该变量的值实际上是硬编码的，而您无法更改它，那么您将无能为力.

You're losing the precision on the assignment, not on the string conversion. If this variable's value is actually hardcoded, and you can't change that, there's nothing you can do.

像这样的一行:

$i = 76561197961384956;

总是会失去精度.如果你需要保留整个东西，把它存成一个字符串，你不能把它存成这样的 int 并保留所有的数字.

will always lose precision. If you need to keep the whole thing, store it into a string, you can't store it as an int like that and keep all the digits.

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