为什么java中的toString方法似乎对数组不起作用 [英] Why does the toString method in java not seem to work for an array
问题描述
我想使用 java 中的 toString() 方法将字符数组转换为字符串对象.这是我使用的测试代码片段:
I want to convert a character array to a string object using the toString() method in java. Here is a snippet of the test code I used:
import java.util.Arrays;
class toString{
public static void main(String[] args){
char[] Array = {'a', 'b', 'c', 'd', 'e', 'f'};
System.out.println(Array.toString());
}
}
原则上应该打印abcdef,但它打印的是[C@6e1408或[C@e53108之类的随机乱码> 每次程序执行时.我不需要其他选择,但想知道为什么会发生这种情况.
In principle, it should print abcdef, but it is printing random gibberish of the likes of [C@6e1408 or [C@e53108 each time the program executes. I don't need an alternative out of this but want to know why this is happening.
推荐答案
要获得人类可读的 toString()
,您必须使用 Arrays.toString()
,像这样:
To get a human-readable toString()
, you must use Arrays.toString()
, like this:
System.out.println(Arrays.toString(Array));
Java 对数组的 toString()
是打印 [
,后跟一个表示数组元素类型的字符(在您的情况下为 C
code> 表示 char
),然后是 @
,然后是数组的身份哈希码"(把它想象成内存地址").
Java's toString()
for an array is to print [
, followed by a character representing the type of the array's elements (in your case C
for char
), followed by @
then the "identity hash code" of the array (think of it like you would a "memory address").
这种可悲的事态通常被认为是 Java 的错误".
This sad state of affairs is generally considered as a "mistake" with java.
有关其他错误"的列表,请参阅此答案.
See this answer for a list of other "mistakes".
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