Spring Data JPA - 用于 json 序列化的 ZonedDateTime 格式 [英] Spring Data JPA - ZonedDateTime format for json serialization

问题描述

我对 ZonedDateTime 的 json 序列化有问题.当转换为 json 时，它会产生一个巨大的对象，我不希望每次都传输所有这些数据.所以我试图将其格式化为 ISO，但它不起作用.我怎样才能让它格式化?

I have a problem with the json serialization of ZonedDateTime. When converted to json it produces an enormous object and I don't want all that data to be transfered every time. So i tried to format it to ISO but it doesn't work. How can i get it to format?

这是我的实体类:

@MappedSuperclass
public abstract class AuditBase {

    @Id
    @GeneratedValue
    private Long id;

    @CreatedDate
    private ZonedDateTime createdDate;

    @LastModifiedDate
    private ZonedDateTime lastModifiedDate;

    @DateTimeFormat(iso = DateTimeFormat.ISO.DATE_TIME)
    public ZonedDateTime getLastModifiedDate() {
        return lastModifiedDate;
    }

    public void setLastModifiedDate(ZonedDateTime lastModifiedDate) {
        this.lastModifiedDate = lastModifiedDate;
    }

    @DateTimeFormat(iso = DateTimeFormat.ISO.DATE_TIME)
    public ZonedDateTime getCreatedDate() {
        return createdDate;
    }

    public void setCreatedDate(ZonedDateTime createdDate) {
        this.createdDate = createdDate;
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    @PrePersist
    public void prePersist() {
        this.createdDate = ZonedDateTime.now();
        this.lastModifiedDate = ZonedDateTime.now();
    }

    @PreUpdate
    public void preUpdate() {
        this.lastModifiedDate = ZonedDateTime.now();
    }
}

推荐答案

我猜你在使用 Jackson 进行 json 序列化，Jackson 现在有一个用于 Java 8 新日期时间 API 的模块，https://github.com/FasterXML/jackson-datatype-jsr310.

I guess that you are using Jackson for json serialization, Jackson now has a module for Java 8 new date time API, https://github.com/FasterXML/jackson-datatype-jsr310.

将此依赖项添加到您的 pom.xml

Add this dependency into your pom.xml

<dependency>
    <groupId>com.fasterxml.jackson.datatype</groupId>
    <artifactId>jackson-datatype-jsr310</artifactId>
    <version>2.6.0</version>
</dependency>

这是它的用法:

 public static void main(String[] args) throws JsonProcessingException {
    ObjectMapper objectMapper = new ObjectMapper();
    objectMapper.registerModule(new JavaTimeModule());
    System.out.println(objectMapper.writeValueAsString(new Entity()));
}

static class Entity {
    ZonedDateTime time = ZonedDateTime.now();

    @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
    public ZonedDateTime getTime() {
        return time;
    }
}

输出为:

{"time":"2015-07-25T23:09:01.795+0700"}

注意:如果您的 Jackson 版本是 2.4.x，请使用

Note : If your Jackson version is 2.4.x use

objectMapper.registerModule(new JSR310Module());

希望这有帮助！

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