如何以分钟为单位找到两个 Joda-Time DateTime 之间的差异 [英] How to find difference between two Joda-Time DateTimes in minutes

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本文介绍了如何以分钟为单位找到两个 Joda-Time DateTime 之间的差异的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

下面是我写的方法:

public List<Map<String, Object>> loadNotYetInEmployee(int shift, Date date,
        int transitionVal, String type, User user) {

    DateTime datetime = new DateTime(date);
    datetime = datetime
            .plus(Period.minutes(shiftTiming.getSession1InTime()));

    List<Map<String, Object>> result = new ArrayList<Map<String, Object>>();

    sql = SqlMapUtils.getSql("attendance.attendancestatus.latein",
            parameters);
    result = getJdbcTemplate().queryForList(sql);
    for (int i = 0; i < result.size(); i++) {
        Date punchInTime = (Date) result.get(i).get("punchtime");
        DateTime punchTime = new DateTime(punchInTime);
    }
    return result;
}

现在从我的方法你可以看到我有一个 Joda-Time DateTime 对象位于名为 datetime 的对象中从我的结果中,我得到了一个时间戳,我将其转换为 jodatime punchTime.现在我想找出这两个日期之间的差异,我该怎么做?

Now from my method you can see I have a Joda-Time DateTime object in object named datetime and from my result I am getting one timestamp which I am converting to jodatime punchTime. Now I want to find out the diff between these two dates, how do I do that?

推荐答案

这将使您以毫秒为单位了解两个 DateTime 对象之间的差异:

This will get you the difference between two DateTime objects in milliseconds:

DateTime d1 = new DateTime();
DateTime d2 = new DateTime();

long diffInMillis = d2.getMillis() - d1.getMillis();

这篇关于如何以分钟为单位找到两个 Joda-Time DateTime 之间的差异的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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