如何将迭代器转换为流? [英] How to convert an Iterator to a Stream?
问题描述
我正在寻找一种简洁的方法来转换 Iterator
到 Stream
或更具体地说,将迭代器查看"为流.
I am looking for a concise way to convert an Iterator
to a Stream
or more specifically to "view" the iterator as a stream.
出于性能原因,我想避免在新列表中复制迭代器:
For performance reason, I would like to avoid a copy of the iterator in a new list:
Iterator<String> sourceIterator = Arrays.asList("A", "B", "C").iterator();
Collection<String> copyList = new ArrayList<String>();
sourceIterator.forEachRemaining(copyList::add);
Stream<String> targetStream = copyList.stream();
<小时>
根据评论中的一些建议,我也尝试使用 Stream.generate
:
public static void main(String[] args) throws Exception {
Iterator<String> sourceIterator = Arrays.asList("A", "B", "C").iterator();
Stream<String> targetStream = Stream.generate(sourceIterator::next);
targetStream.forEach(System.out::println);
}
但是,我得到一个 NoSuchElementException
(因为没有调用 hasNext
)
However, I get a NoSuchElementException
(since there is no invocation of hasNext
)
Exception in thread "main" java.util.NoSuchElementException
at java.util.AbstractList$Itr.next(AbstractList.java:364)
at Main$$Lambda$1/1175962212.get(Unknown Source)
at java.util.stream.StreamSpliterators$InfiniteSupplyingSpliterator$OfRef.tryAdvance(StreamSpliterators.java:1351)
at java.util.Spliterator.forEachRemaining(Spliterator.java:326)
at java.util.stream.ReferencePipeline$Head.forEach(ReferencePipeline.java:580)
at Main.main(Main.java:20)
我看过StreamSupport
和 集合
但我什么也没找到.
I have looked at StreamSupport
and Collections
but I didn't find anything.
推荐答案
一种方法是从 Iterator
创建一个 Spliterator
并将其用作流的基础:
One way is to create a Spliterator
from the Iterator
and use that as a basis for your stream:
Iterator<String> sourceIterator = Arrays.asList("A", "B", "C").iterator();
Stream<String> targetStream = StreamSupport.stream(
Spliterators.spliteratorUnknownSize(sourceIterator, Spliterator.ORDERED),
false);
另一种可能更具可读性的替代方法是使用 Iterable
- 使用 lambda 从 Iterator
创建一个 Iterable
非常容易,因为Iterable
是一个函数式接口:
An alternative which is maybe more readable is to use an Iterable
- and creating an Iterable
from an Iterator
is very easy with lambdas because Iterable
is a functional interface:
Iterator<String> sourceIterator = Arrays.asList("A", "B", "C").iterator();
Iterable<String> iterable = () -> sourceIterator;
Stream<String> targetStream = StreamSupport.stream(iterable.spliterator(), false);
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