流和惰性求值 [英] Stream and lazy evaluation

问题描述

我正在阅读 java 8 API 关于流抽象但是这句话我不是很懂:

I'm reading from the java 8 API on the stream abstraction but I don't understand this sentence very well:

中间操作返回一个新的流.他们总是懒惰；执行诸如 filter() 之类的中间操作实际上并没有执行任何过滤，而是创建一个新的流，当遍历，包含匹配的初始流的元素给定谓词.管道源的遍历直到执行管道的终端操作.

Intermediate operations return a new stream. They are always lazy; executing an intermediate operation such as filter() does not actually perform any filtering, but instead creates a new stream that, when traversed, contains the elements of the initial stream that match the given predicate. Traversal of the pipeline source does not begin until the terminal operation of the pipeline is executed.

当过滤操作创建新流时，该流是否包含过滤元素?似乎理解流仅在被遍历时才包含元素，即使用终端操作.但是，过滤后的流包含什么?我糊涂了！！！

When a filter operation creates a new stream does that stream contain a filtered element? It seems to understand that the stream contains elements only when it is traversed i.e with a terminal operation. But, then, what does the filtered stream contain? I'm confused!!!

推荐答案

表示过滤器只在终端操作时应用.想想这样的事情:

It means that the filter is only applied during the terminal operation. Think of something like this:

public Stream filter(Predicate p) {
    this.filter = p; // just store it, don't apply it yet
    return this; // in reality: return a new stream
}
public List collect() {
    for (Object o : stream) {
        if (filter.test(o)) list.add(o);
    }
    return list;
}

(那不编译，是对现实的简化，但原理是存在的)

(That does not compile and is a simplification of the reality but the principle is there)

这篇关于流和惰性求值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！