如何在 x86 汇编编程中表示 FFFFFFBB 等十六进制值? [英] How to represent hex value such as FFFFFFBB in x86 assembly programming?

问题描述

我正在学习 x86 内联汇编编程.

I'm learning about x86 inline assembly programming.

我想写 mov ecx, FFFFFFBB，但是编译器无法识别它.内联汇编代码应该如何编写这样的十六进制数字?

I wanted to write mov ecx, FFFFFFBB, however the compiler isn’t recognizing it. How should hex numbers like that be written in inline assembler code?

推荐答案

这取决于你的汇编程序的风格.

It depends on the flavour of your assembler.

• AT&T:movl $0xFFFFFFBB, %ecx
• 英特尔:mov ecx, 0FFFFFFBBh

仅供参考，GNU Assembler 等汇编器使用 AT&T 语法，而 NASM 和其他大多数使用英特尔的语法.

FYI, AT&T syntax is used by assemblers such as the GNU Assembler, whereas NASM and most of others use Intel's one.

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