如何解决属性错误“float"对象在python中没有属性“split"? [英] How to solve the Attribute error 'float' object has no attribute 'split' in python?

查看:124
本文介绍了如何解决属性错误“float"对象在python中没有属性“split"?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

当我运行下面的代码时,它给我一个错误,说存在属性错误:'float' object has no attribute 'split' in python.

When I run the below code, it gives me an error saying that there is attribute error: 'float' object has no attribute 'split' in python.

我想知道为什么会出现这个错误.

I would like to know why this error comes about.

def text_processing(df):

    """""=== Lower case ==="""
    '''First step is to transform comments into lower case'''
    df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words))

    return df

df = text_processing(df)

错误的完整回溯:

Traceback (most recent call last):
  File "C:Program FilesJetBrainsPyCharm Community Edition 2018.2.2helperspydevpydevd.py", line 1664, in <module>
    main()
  File "C:Program FilesJetBrainsPyCharm Community Edition 2018.2.2helperspydevpydevd.py", line 1658, in main
    globals = debugger.run(setup['file'], None, None, is_module)
  File "C:Program FilesJetBrainsPyCharm Community Edition 2018.2.2helperspydevpydevd.py", line 1068, in run
    pydev_imports.execfile(file, globals, locals)  # execute the script
  File "C:Program FilesJetBrainsPyCharm Community Edition 2018.2.2helperspydev\_pydev_imps\_pydev_execfile.py", line 18, in execfile
    exec(compile(contents+"
", file, 'exec'), glob, loc)
  File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 53, in <module>
    df = text_processing(df)
  File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 30, in text_processing
    df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words))
  File "C:UsersL31307AppDataRoamingPythonPython37site-packagespandascoreseries.py", line 3194, in apply
    mapped = lib.map_infer(values, f, convert=convert_dtype)
  File "pandas/_libs/srcinference.pyx", line 1472, in pandas._libs.lib.map_infer
  File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 30, in <lambda>
    df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words))
AttributeError: 'float' object has no attribute 'split'

推荐答案

错误指向这一行:

df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() 
                                    if x not in stop_words))

split 在这里用作 Python 内置 str 类的方法.您的错误表明 df['content'] 中的一个或多个值属于 float 类型.这可能是因为存在空值,即 NaN,或非空浮点值.

split is being used here as a method of Python's built-in str class. Your error indicates one or more values in df['content'] is of type float. This could be because there is a null value, i.e. NaN, or a non-null float value.

一种将浮点数字符串化的解决方法是在使用 split 之前在 x 上应用 str:

One workaround, which will stringify floats, is to just apply str on x before using split:

df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in str(x).split() 
                                    if x not in stop_words))

或者,可能是更好的解决方案,明确并使用带有 try/except 子句的命名函数:

Alternatively, and possibly a better solution, be explicit and use a named function with a try / except clause:

def converter(x):
    try:
        return ' '.join([x.lower() for x in str(x).split() if x not in stop_words])
    except AttributeError:
        return None  # or some other value

df['content'] = df['content'].apply(converter)

由于 pd.Series.apply 只是一个有开销的循环,你可能会发现列表理解或 map 更有效:

Since pd.Series.apply is just a loop with overhead, you may find a list comprehension or map more efficient:

df['content'] = [converter(x) for x in df['content']]
df['content'] = list(map(converter, df['content']))

这篇关于如何解决属性错误“float"对象在python中没有属性“split"?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
相关文章
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆