转置/解压缩功能(zip 的反函数)? [英] Transpose/Unzip Function (inverse of zip)?

问题描述

我有一个 2 项元组列表，我想将它们转换为 2 个列表，其中第一个包含每个元组中的第一个项目，第二个列表包含第二个项目.

例如:

original = [('a', 1), ('b', 2), ('c', 3), ('d', 4)]#我想成为...结果 = (['a', 'b', 'c', 'd'], [1, 2, 3, 4])

是否有内置函数可以做到这一点?

解决方案

zip 是它自己的逆！前提是您使用了特殊的 * 运算符.

<预><代码>>>>zip(*[('a', 1), ('b', 2), ('c', 3), ('d', 4)])[('a', 'b', 'c', 'd'), (1, 2, 3, 4)]

它的工作方式是使用参数调用 zip:

zip(('a', 1), ('b', 2), ('c', 3), ('d', 4))

...除了参数直接传给zip(转成元组后)，所以不用担心参数个数过大.

I have a list of 2-item tuples and I'd like to convert them to 2 lists where the first contains the first item in each tuple and the second list holds the second item.

For example:

original = [('a', 1), ('b', 2), ('c', 3), ('d', 4)]
# and I want to become...
result = (['a', 'b', 'c', 'd'], [1, 2, 3, 4])

Is there a builtin function that does that?

解决方案

zip is its own inverse! Provided you use the special * operator.

>>> zip(*[('a', 1), ('b', 2), ('c', 3), ('d', 4)])
[('a', 'b', 'c', 'd'), (1, 2, 3, 4)]

The way this works is by calling zip with the arguments:

zip(('a', 1), ('b', 2), ('c', 3), ('d', 4))

… except the arguments are passed to zip directly (after being converted to a tuple), so there's no need to worry about the number of arguments getting too big.

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