makefile:4: *** 缺少分隔符.停止 [英] makefile:4: *** missing separator. Stop

问题描述

这是我的生成文件:

all:ll

ll:ll.c   
  gcc  -c  -Wall -Werror -02 c.c ll.c  -o  ll  $@  $<

clean :
  
m -fr ll

当我尝试 make clean 或 make make 时，我收到此错误:

When I try to make clean or make make, I get this error:

:makefile:4: *** missing separator.  Stop.

我该如何解决?

推荐答案

make 与制表符的关系非常愚蠢.每个规则的所有操作都由选项卡标识.而且，不，四个空格不能构成一个制表符.只有标签才能成为标签.

make has a very stupid relationship with tabs. All actions of every rule are identified by tabs. And, no, four spaces don't make a tab. Only a tab makes a tab.

为了检查，我使用命令 cat -e -t -v makefile_name.

To check, I use the command cat -e -t -v makefile_name.

它显示了带有 ^I 的制表符和带有 $ 的行结尾.两者对于确保依赖项正确结束都很重要，选项卡标记规则的操作，以便 make 实用程序可以轻松识别它们.

It shows the presence of tabs with ^I and line endings with $. Both are vital to ensure that dependencies end properly and tabs mark the action for the rules so that they are easily identifiable to the make utility.

示例:

Kaizen ~/so_test $ cat -e -t -v  mk.t
all:ll$      ## here the $ is end of line ...                   
$
ll:ll.c   $
^Igcc  -c  -Wall -Werror -02 c.c ll.c  -o  ll  $@  $<$ 
## the ^I above means a tab was there before the action part, so this line is ok .
 $
clean :$
   
m -fr ll$
## see here there is no ^I which means , tab is not present .... 
## in this case you need to open the file again and edit/ensure a tab 
## starts the action part

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