如何解析JSON并获取结果 [英] How to parse JSON and access results

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本文介绍了如何解析JSON并获取结果的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用 CURL 发送请求.响应数据类型是 json.如何解析这些数据并将其插入到数据库中?

I am using CURL to send a request. The response dataType is json. How can I parse this data and insert it into the database?

<?php

$url = 'http://sms2.cdyne.com/sms.svc/SimpleSMSsendWithPostback?        PhoneNumber=18887477474&Message=test&LicenseKey=LICENSEKEY';

$cURL = curl_init();

curl_setopt($cURL, CURLOPT_URL, $url);
curl_setopt($cURL, CURLOPT_HTTPGET, true);

curl_setopt($cURL, CURLOPT_HTTPHEADER, array(
    'Content-Type: application/json',
    'Accept: application/json'
));

$result = curl_exec($cURL);

curl_close($cURL);



print_r($result);

?>

JSON 输出:

{
    "Cancelled": false,
    "MessageID": "402f481b-c420-481f-b129-7b2d8ce7cf0a",
    "Queued": false,
    "SMSError": 2,
    "SMSIncomingMessages": null,
    "Sent": false,
    "SentDateTime": "/Date(-62135578800000-0500)/"
}

推荐答案

如果你的 $result 变量是一个类似 json 的字符串,你必须使用 json_decode 函数来解析它作为对象数组:

If your $result variable is a string json like, you must use json_decode function to parse it as an object or array:

$result = '{"Cancelled":false,"MessageID":"402f481b-c420-481f-b129-7b2d8ce7cf0a","Queued":false,"SMSError":2,"SMSIncomingMessages":null,"Sent":false,"SentDateTime":"/Date(-62135578800000-0500)/"}';
$json = json_decode($result, true);
print_r($json);

输出

Array
(
    [Cancelled] => 
    [MessageID] => 402f481b-c420-481f-b129-7b2d8ce7cf0a
    [Queued] => 
    [SMSError] => 2
    [SMSIncomingMessages] => 
    [Sent] => 
    [SentDateTime] => /Date(-62135578800000-0500)/
)

现在您可以将 $json 变量用作数组:

Now you can work with $json variable as an array:

echo $json['MessageID'];
echo $json['SMSError'];
// other stuff


参考文献:


References:

  • json_decode - PHP Manual

这篇关于如何解析JSON并获取结果的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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