生成随机的唯一值 C# [英] Generating random, unique values C#

查看:32
本文介绍了生成随机的唯一值 C#的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我已经搜索了一段时间并且一直在努力找到这个,我正在尝试生成几个随机的、唯一的数字是 C#.我正在使用 System.Random,我正在使用 DateTime.Now.Ticks 种子:

I've searched for a while and been struggling to find this, I'm trying to generate several random, unique numbers is C#. I'm using System.Random, and I'm using a DateTime.Now.Ticks seed:

public Random a = new Random(DateTime.Now.Ticks.GetHashCode());
private void NewNumber()
{
    MyNumber = a.Next(0, 10);
}

我定期调用 NewNumber(),但问题是我经常收到重复的数字.有人建议,因为我每次都声明随机数,它不会产生随机数,所以我把声明放在我的函数之外.有什么建议或比使用 System.Random 更好的方法?谢谢

I'm calling NewNumber() regularly, but the problem is I often get repeated numbers. Some people suggested because I was declaring the random every time I did it, it would not produce a random number, so I put the declaration outside my function. Any suggestions or better ways than using System.Random ? Thank you

推荐答案

我经常调用 NewNumber(),但问题是我经常遇到重复的数字.

I'm calling NewNumber() regularly, but the problem is I often get repeated numbers.

Random.Next 不保证数字是唯一的.此外,您的范围是从 0 到 10,您可能会得到重复的值.也许您可以设置一个 int 列表,并在检查它是否不包含重复项后在列表中插入随机数.类似的东西:

Random.Next doesn't guarantee the number to be unique. Also your range is from 0 to 10 and chances are you will get duplicate values. May be you can setup a list of int and insert random numbers in the list after checking if it doesn't contain the duplicate. Something like:

public Random a = new Random(); // replace from new Random(DateTime.Now.Ticks.GetHashCode());
                                // Since similar code is done in default constructor internally
public List<int> randomList = new List<int>();
int MyNumber = 0;
private void NewNumber()
{
    MyNumber = a.Next(0, 10);
    if (!randomList.Contains(MyNumber))
        randomList.Add(MyNumber);
}

这篇关于生成随机的唯一值 C#的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆