如何快速获取IP地址 [英] How to get Ip address in swift

问题描述

如何获取我的本地 IP 地址?

How do i get my local IpAddress?

我尝试使用这个 Obj C 示例:如何以编程方式获取iphone的IP地址

I tried to use this Obj C example: how to get ip address of iphone programmatically

当我到达函数 getifaddrs() 时，我不能再进一步了.我无法使用该功能.

When i get to the function getifaddrs() i can't get any further. i can't use the function.

是否有其他方法可以做到这一点，还是我的方法错误?

Is there an alternative way to do this, or am I approaching this the wrong way?

推荐答案

正如在讨论中所证明的那样，OP 需要 Mac 上的接口地址，而不是我最初认为的 iOS 设备上的接口地址.问题中引用的代码检查接口名称en0"，即iPhone上的WiFi接口.在 Mac 上它使更多相反，检查任何启动并运行"的界面是有意义的.因此，我重写了答案.它现在是代码的 Swift 翻译检测任何连接的网络.

As it turned out in the discussion, OP needs the interface address on a Mac and not on an iOS device as I thought initially. The code referenced in the question checks for the interface name "en0", which is the WiFi interface on the iPhone. On a Mac it makes more sense to check for any "up-and-running" interface instead. Therefore I have rewritten the answer. It is now a Swift translation of the code in Detect any connected network.

getifaddrs() 定义在 中，默认不包含.因此，您必须创建一个桥接头并添加

getifaddrs() is defined in <ifaddrs.h>, which is not included by default. Therefore you have to create a bridging header and add

#include <ifaddrs.h>

以下函数返回一个包含所有本地正常运行"网络接口名称的数组.

The following function returns an array with the names of all local "up-and-running" network interfaces.

func getIFAddresses() -> [String] {
    var addresses = [String]()

    // Get list of all interfaces on the local machine:
    var ifaddr : UnsafeMutablePointer<ifaddrs> = nil
    if getifaddrs(&ifaddr) == 0 {

        // For each interface ...
        var ptr = ifaddr
        while ptr != nil {
            defer { ptr = ptr.memory.ifa_next } 

            let flags = Int32(ptr.memory.ifa_flags)
            let addr = ptr.memory.ifa_addr.memory

            // Check for running IPv4, IPv6 interfaces. Skip the loopback interface.
            if (flags & (IFF_UP|IFF_RUNNING|IFF_LOOPBACK)) == (IFF_UP|IFF_RUNNING) {
                if addr.sa_family == UInt8(AF_INET) || addr.sa_family == UInt8(AF_INET6) {

                    // Convert interface address to a human readable string:
                    var hostname = [CChar](count: Int(NI_MAXHOST), repeatedValue: 0)
                    if (getnameinfo(ptr.memory.ifa_addr, socklen_t(addr.sa_len), &hostname, socklen_t(hostname.count),
                        nil, socklen_t(0), NI_NUMERICHOST) == 0) {
                        if let address = String.fromCString(hostname) {
                            addresses.append(address)
                        }
                    }
                }
            }
        }
        freeifaddrs(ifaddr)
    }

    return addresses
}

<小时>

Swift 3 的更新:除了采用代码到Swift 3 中的许多变化，迭代所有接口现在可以使用新的通用化sequence() 函数:

---

Update for Swift 3: In addition to adopting the code to the many changes in Swift 3, iterating over all interfaces can now use the new generalized sequence() function:

func getIFAddresses() -> [String] {
    var addresses = [String]()

    // Get list of all interfaces on the local machine:
    var ifaddr : UnsafeMutablePointer<ifaddrs>?
    guard getifaddrs(&ifaddr) == 0 else { return [] }
    guard let firstAddr = ifaddr else { return [] }

    // For each interface ...
    for ptr in sequence(first: firstAddr, next: { $0.pointee.ifa_next }) {
        let flags = Int32(ptr.pointee.ifa_flags)
        let addr = ptr.pointee.ifa_addr.pointee

        // Check for running IPv4, IPv6 interfaces. Skip the loopback interface.
        if (flags & (IFF_UP|IFF_RUNNING|IFF_LOOPBACK)) == (IFF_UP|IFF_RUNNING) {
            if addr.sa_family == UInt8(AF_INET) || addr.sa_family == UInt8(AF_INET6) {

                // Convert interface address to a human readable string:
                var hostname = [CChar](repeating: 0, count: Int(NI_MAXHOST))
                if (getnameinfo(ptr.pointee.ifa_addr, socklen_t(addr.sa_len), &hostname, socklen_t(hostname.count),
                                nil, socklen_t(0), NI_NUMERICHOST) == 0) {
                    let address = String(cString: hostname)
                    addresses.append(address)
                }
            }
        }
    }

    freeifaddrs(ifaddr)
    return addresses
}

这篇关于如何快速获取IP地址的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！