如何在 Swift 3 中编程延迟 [英] How to program a delay in Swift 3

问题描述

在早期版本的 Swift 中，可以使用以下代码创建延迟:

In earlier versions of Swift, one could create a delay with the following code:

let time = dispatch_time(dispatch_time_t(DISPATCH_TIME_NOW), 4 * Int64(NSEC_PER_SEC))
dispatch_after(time, dispatch_get_main_queue()) {
    //put your code which should be executed with a delay here
}

但是现在，在 Swift 3 中，Xcode 会自动更改 6 种不同的内容，但随后出现以下错误:无法将 DispatchTime.now 转换为预期值 dispatch_time_t aka UInt64."

But now, in Swift 3, Xcode automatically changes 6 different things but then the following error appears: "Cannot convert DispatchTime.now to expected value dispatch_time_t aka UInt64."

如何在 Swift 3 中运行一系列代码之前创建延迟?

How can one create a delay before running a sequence of code in Swift 3?

推荐答案

经过大量研究，我终于想出了这个.

After a lot of research, I finally figured this one out.

DispatchQueue.main.asyncAfter(deadline: .now() + 2.0) { // Change `2.0` to the desired number of seconds.
   // Code you want to be delayed
}

这会在 Swift 3 和 Swift 4 中创建所需的等待"效果.

This creates the desired "wait" effect in Swift 3 and Swift 4.

受到这个答案的一部分的启发.

这篇关于如何在 Swift 3 中编程延迟的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！