基于 int 创建多个编号变量 [英] Create multiple numbered variables based on a int

问题描述

如何使用数组的计数创建多个 NSDictionary 变量?

How would I create a number of NSDictionary variables using an array's count?

这基本上是我想出的，但我不确定如何使用 Objective-C 语法使其工作.doesntContainAnother 是一个 NSArray.我希望字典的名称使用 loopInt 的当前值.

This is basically what I came up with, but I'm not sure how to make this work with Objective-C syntax. doesntContainAnother is an NSArray. I want the names of the dictionaries to use the current value of loopInt.

int *loopInt = 0;
while (doesntContainAnother.count <= loopInt) {

    NSMutableDictionary *[NSString stringWithFormat:@"loopDictionary%i", loopInt] = [[[NSMutableDictionary alloc] init] autorelease];
    [NSString stringWithFormat:@"loopDictionary%i", loopInt] = [NSDictionary dictionaryWithObject:[array1 objectAtIndex:loopInt] 
                                                 forKey:[array2 objectAtIndex:loopInt]];
    loopInt = loopInt + 1;
}

推荐答案

创建一个可变数组并循环直到达到原始数组的计数，创建一个字典并在每次迭代时将其添加到可变数组中.

Create a mutable array and loop until you reach the original array's count, creating a dictionary and adding it to the mutable array on each iteration.

您的代码应如下所示.

NSMutableArray *dictionaries = [[NSMutableArray alloc] init];
for (int i = 0; i < doesntContainAnother.count; i++) {
    [dictionaries addObject:[NSMutableDictionary dictionaryWithObject:[array1 objectAtIndex:i] forKey:[array2 objectAtIndex:i]]];
}

创建变量名末尾带有数字的方法是一种反模式，甚至在 Objective-C 中是不可能的.它相当于一个数组，但更笨重.

The approach of creating variables with numbers at the end of their names is an antipattern and not even possible in Objective-C. It's equivalent to an array, but clunkier.

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