如何在 find 命令中使用正则表达式? [英] How to use regex with find command?

问题描述

我有一些用生成的 uuid1 字符串命名的图像.例如 81397018-b84a-11e0-9d2a-001b77dc0bed.jpg.我想使用查找"命令找出所有这些图像:

I have some images named with generated uuid1 string. For example 81397018-b84a-11e0-9d2a-001b77dc0bed.jpg. I want to find out all these images using "find" command:

find . -regex "[a-f0-9-]{36}.jpg".

但它不起作用.正则表达式有问题吗?有人可以帮我解决这个问题吗?

But it doesn't work. Something wrong with the regex? Could someone help me with this?

推荐答案

find . -regextype sed -regex ".*/[a-f0-9-]{36}.jpg"

注意需要在开头指定.*/，因为find匹配整个路径.

Note that you need to specify .*/ in the beginning because find matches the whole path.

示例:

susam@nifty:~/so$ find . -name "*.jpg"
./foo-111.jpg
./test/81397018-b84a-11e0-9d2a-001b77dc0bed.jpg
./81397018-b84a-11e0-9d2a-001b77dc0bed.jpg
susam@nifty:~/so$ 
susam@nifty:~/so$ find . -regextype sed -regex ".*/[a-f0-9-]{36}.jpg"
./test/81397018-b84a-11e0-9d2a-001b77dc0bed.jpg
./81397018-b84a-11e0-9d2a-001b77dc0bed.jpg

我的查找版本:

$ find --version
find (GNU findutils) 4.4.2
Copyright (C) 2007 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.

Written by Eric B. Decker, James Youngman, and Kevin Dalley.
Built using GNU gnulib version e5573b1bad88bfabcda181b9e0125fb0c52b7d3b
Features enabled: D_TYPE O_NOFOLLOW(enabled) LEAF_OPTIMISATION FTS() CBO(level=0) 
susam@nifty:~/so$ 
susam@nifty:~/so$ find . -regextype foo -regex ".*/[a-f0-9-]{36}.jpg"
find: Unknown regular expression type `foo'; valid types are `findutils-default', `awk', `egrep', `ed', `emacs', `gnu-awk', `grep', `posix-awk', `posix-basic', `posix-egrep', `posix-extended', `posix-minimal-basic', `sed'.

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