从 HTML 标签中删除样式属性 [英] Remove style attribute from HTML tags

问题描述

我不太擅长正则表达式，但是对于 PHP，我想从 TinyMCE 返回的字符串中的 HTML 标记中删除 style 属性.

I'm not too good with regular expressions, but with PHP I'm wanting to remove the style attribute from HTML tags in a string that's coming back from TinyMCE.

因此将 <p style="...">Text</p> 更改为普通的 <p>Test</p>.

So change <p style="...">Text</p> to just vanilla <p>Test</p>.

我将如何使用 preg_replace() 函数来实现这一点?

How would I achieve this with something like the preg_replace() function?

推荐答案

实用的正则表达式 (<[^>]+) style=".*?" 将解决这个问题在所有合理的情况下.应该删除不是第一个捕获组的匹配部分，如下所示:

The pragmatic regex (<[^>]+) style=".*?" will solve this problem in all reasonable cases. The part of the match that is not the first captured group should be removed, like this:

$output = preg_replace('/(<[^>]+) style=".*?"/i', '$1', $input);

匹配一个 < 后跟一个或多个not >"；直到我们来到 space 和 style="..." 部分./i 使它在 STYLE="..." 的情况下也能工作.将此匹配替换为 $1，即捕获的组.如果标签不包含 style="..."，它将保持原样.

Match a < followed by one or more "not >" until we come to space and the style="..." part. The /i makes it work even with STYLE="...". Replace this match with $1, which is the captured group. It will leave the tag as is, if the tag doesn't include style="...".

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