在 PHP 中捕获方括号之间的文本 [英] Capturing text between square brackets in PHP

问题描述

我需要某种方法来捕获方括号之间的文本.例如，以下字符串:

I need some way of capturing the text between square brackets. So for example, the following string:

【这个】是一个【测试】字符串，【吃】我的【短裤】.

可用于创建以下数组:

Array ( 
     [0] => [This] 
     [1] => [test] 
     [2] => [eat] 
     [3] => [shorts] 
)

我有以下正则表达式，/[.*?]/ 但它只捕获第一个实例，所以:

I have the following regex, /[.*?]/ but it only captures the first instance, so:

Array ( [0] => [This] )

我怎样才能得到我需要的输出?请注意，方括号从不嵌套，因此不必担心.

How can I get the output I need? Note that the square brackets are NEVER nested, so that's not a concern.

推荐答案

匹配所有带括号的字符串:

Matches all strings with brackets:

$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/[[^]]*]/", $text, $matches);
var_dump($matches[0]);

如果你想要没有括号的字符串:

If You want strings without brackets:

$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/[([^]]*)]/", $text, $matches);
var_dump($matches[1]);

另一种较慢的不带括号匹配版本(使用*"代替[^]"):

Alternative, slower version of matching without brackets (using "*" instead of "[^]"):

$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/[(.*?)]/", $text, $matches);
var_dump($matches[1]);

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