扩展 bash 数组只给出第一个元素 [英] Expanding a bash array only gives the first element

问题描述

我想把当前目录的文件放在一个数组中，并用这个脚本回显每个文件:

I want to put the files of the current directory in an array and echo each file with this script:

#!/bin/bash

files=(*)

for file in $files
do
    echo $file
done

# This demonstrates that the array in fact has more values from (*)
echo ${files[0]}  ${files[1]} 

echo done

输出:

echo.sh
echo.sh read_output.sh
done

有谁知道为什么在这个 for 循环中只打印第一个元素?

Does anyone know why only the first element is printed in this for loop?

推荐答案

$files 扩展到数组的第一个元素.试试 echo $files，它只会打印数组的第一个元素.出于同样的原因，for 循环只打印一个元素.

$files expands to the first element of the array. Try echo $files, it will only print the first element of the array. The for loop prints only one element for the same reason.

要扩展到数组的所有元素，您需要编写为 ${files[@]}.

To expand to all elements of the array you need to write as ${files[@]}.

迭代 Bash 数组元素的正确方法:

The correct way to iterate over elements of a Bash array:

for file in "${files[@]}"

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