如何使用 Cocoa api 启动应用程序并将其置于前台? [英] How to launch application and bring it to front using Cocoa api?

问题描述

我对可可编程非常陌生，我找不到执行以下操作的方法:

I'm very new to a cocoa programming and I can't find the way to do the following:

• 按名称启动特定应用程序
• 做一些工作
• 稍后带来应用程序，我开始成为前端流程

从我在 Carbon API 中发现的内容来看，我应该使用的调用是 launchApplication() 和 setFrontProcess().

From what I've found in Carbon API it looks like the calls i should use are launchApplication() and setFrontProcess().

但是如何在 Cocoa 中做到这一点?IE.启动它，获取 PID，将该 PID 设置为前端进程.我试着用谷歌搜索例子，但一无所获......

But how to do this in Cocoa? I.e. launch it, get PID, set that PID to be a front process. I tried to google for examples and find nothing...

如果你们中的任何人都可以提供一个很棒的极简示例:)

If any of you can provide a minimalistic sample that would be awesome :)

提前致谢.

推荐答案

启动应用程序:

[[NSWorkspace sharedWorkspace] launchApplication:@"/Applications/Safari.app"];

激活应用程序:

NSRunningApplication* app = [NSRunningApplication
                             runningApplicationWithProcessIdentifier: PID];
[app activateWithOptions: NSApplicationActivateAllWindows];
// or
NSArray* apps = [NSRunningApplication
                 runningApplicationsWithBundleIdentifier:@"com.bla.blah"];
[(NSRunningApplication*)[apps objectAtIndex:0]
 activateWithOptions: NSApplicationActivateAllWindows];

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