将额外的参数传递给 Django Rest Framework 中的序列化器类 [英] Pass extra arguments to Serializer Class in Django Rest Framework

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问题描述

我想将一些参数从 Viewset 传递给 DRF Serializer 类,所以我已经尝试过:

I want to pass some arguments to DRF Serializer class from Viewset, so for I have tried this:

class OneZeroSerializer(rest_serializer.ModelSerializer):

    def __init__(self, *args, **kwargs):
        print args # show values that passed

    location = rest_serializer.SerializerMethodField('get_alternate_name')

    def get_alternate_name(self, obj):
        return ''


    class Meta:
        model = OneZero

        fields = ('id', 'location')

观看次数

class OneZeroViewSet(viewsets.ModelViewSet):

   serializer_class = OneZeroSerializer(realpart=1)
   #serializer_class = OneZeroSerializer

   queryset = OneZero.objects.all()

基本上,我想将一些基于查询字符串的值从视图传递给 Serializer 类,然后这些值将分配给字段.

Basically I want to pass some value based on querystring from views to Serializer class and then these will be allocate to fields.

这些字段实际上不包含在模型中,实际上是动态创建的字段.

These fields are not include in Model in fact dynamically created fields.

这个问题的情况相同stackoverflow,但我无法理解答案.

Same case in this question stackoverflow, but I cannot understand the answer.

任何人都可以在这种情况下帮助我或建议我更好的选择.

Can anyone help me in this case or suggest me better options.

推荐答案

ModelSerializer"构造函数的context"参数非常容易.

It's very easy with "context" arg for "ModelSerializer" constructor.

例如:

在视图中:

my_objects = MyModelSerializer(
    input_collection, 
    many=True, 
    context={'user_id': request.user.id}
).data

在序列化器中:

class MyModelSerializer(serializers.ModelSerializer):
...

    is_my_object = serializers.SerializerMethodField('_is_my_find')
...

    def _is_my_find(self, obj):
        user_id = self.context.get("user_id")
        if user_id:
            return user_id in obj.my_objects.values_list("user_id", flat=True)
        return False
...

所以你可以使用self.context"来获取额外的参数.

so you can use "self.context" for getting extra params.

参考

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