REST API 中搜索的响应状态代码 [英] Response status code for searches in REST APIs

问题描述

假设我们有以下 API:

Suppose, we have the following API:

GET /api/guests/{id}

GET /api/guests?name=dummy

如果没有客人符合条件，我应该返回哪个状态代码?我的意思是没有名字叫dummy的客人.

Which status code should I return when there are no guests matching criteria? I mean no guests with name dummy.

应该是404、204还是200，数组为空?

Should it be 404, 204 or 200 with an empty array?

推荐答案

我会用一个空数组返回 200...
或 204(无内容)

I would return 200 with an empty array...
Or a 204 (No Content)

404 是指找不到资源.在这种情况下，您的资源是客人的集合......存在.

A 404 is when a resource isn't found. Your resource in this case is the collection of guests... which exists.

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