正则表达式拆分字符串但保留分隔符 [英] Regex split string but keep separators

问题描述

我想对某些对象执行 Regex.Split分隔符，但我想保留分隔符.举一个我正在尝试的例子:

I'd like to do a Regex.Split on some separators but I'd like to keep the separators. To give an example of what I'm trying:

"abc[s1]def[s2][s3]ghi" --> "abc", "[s1]", "def", "[s2]", "[s3]", "ghi"

我想出的正则表达式是 new Regex("\[|\]|\]\[").但是，这给了我以下内容:

The regular expression I've come up with is new Regex("\[|\]|\]\["). However, this gives me the following:

"abc[s1]def[s2][s3]ghi" --> "abc", "s1", "def", "s2", "", "s3", "ghi"

分隔符消失了(考虑到我的正则表达式，这是有道理的).有没有办法编写正则表达式，以便保留分隔符本身?

The separators have disappeared (which makes sense given my regex). Is there a way to write the regex so that the separators themselves are preserved?

推荐答案

Use zero-length maching lookarounds;你想分开

Use zero-length maching lookarounds; you want to split on

(?=[)|(?<=])

也就是说，我们在前面断言文字 [ 匹配的任何地方，或者在后面断言文字 ] 匹配的任何地方.

That is, anywhere where we assert a match of a literal [ ahead, or where we assert a match of literal ] behind.

作为 C# 字符串文字，这是

As a C# string literal, this is

@"(?=[)|(?<=])"

另见

• regular-expressions.info/Lookarounds
• Java split 正在吞噬我的角色. -- 有很多例子
• Java split is eating my characters. -- has many examples

    System.out.println(java.util.Arrays.toString(
        "abc[s1]def[s2][s3]ghi".split("(?=\[)|(?<=\])")
    ));
    // prints "[abc, [s1], def, [s2], [s3], ghi]"

    System.out.println(java.util.Arrays.toString(
        "abc;def;ghi;".split("(?<=;)")
    ));
    // prints "[abc;, def;, ghi;]"

    System.out.println(java.util.Arrays.toString(
        "OhMyGod".split("(?=(?!^)[A-Z])")
    ));
    // prints "[Oh, My, God]"

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