为什么我们不能重写一个方法并将其定义为返回原始方法的超类? [英] why we can't override a method and define it to return a superclass of the original method?
问题描述
I'm currently learning Java classes and objects from java tutorial oracle and have encountered the following statements and code. I understand the concept but I do not know why we can't override a method and define it to return a superclass of the original method? What is the reason behind it? Could someone please enlighten me? Thanks in advance for any help!
你可以重写一个方法并定义它来返回一个子类原来的方法,像这样:
You can override a method and define it to return a subclass of the original method, like this:
public Number returnANumber() {
...
}
覆盖原来的方法:
public ImaginaryNumber returnANumber() {
...
}
推荐答案
想象一下,如果可能的话:
Imagine if it was possible:
public class CarFactory {
Car giveMeACar() { ... };
}
public class SpecialCarFactory extends CarFactory {
@Override
Object giveMeACar() {
return "hello world";
}
)
public class Driver {
void drive() {
CarFactory carFactory = new SpecialCarFactory();
Car car = carFactory.giveMeACar();
// err, wait, sorry, can't do that.
// This car factory, despite its name, doesn't produce cars.
// It produces objects, and I've heard they're just
// "hello world" strings. Good luck driving a "hello world"
// string on a highway!
}
}
看,这只是合同的事情.当你去咖啡店时,你希望它卖咖啡.不遵守本合同的东西不能称为咖啡店":咖啡店必须卖咖啡.它可以出售挤奶咖啡,因为挤奶咖啡仍然是咖啡.(就像汽车厂只能生产丰田,因为丰田是一辆汽车,你可以像驾驶其他汽车一样驾驶丰田,甚至不知道它是丰田:这就是多态性.
See, it's just a contract thing. When you go to a coffee shop, you expect it to sell coffee. Something can't be called "a coffee shop" if it doesn't comply to this contract: a coffee shop must sell coffee. It can sell milked coffee, because a milked coffee is still a coffee. (just like a car factory can produce Toyota only, because Toyota is a car, and you can drive a Toyota like any other car, without even knowing it's a Toyota: that's polymorphism).
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