MYSQL where 子句中的条件 [英] Conditional in MYSQL where clause

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问题描述

我有一个查询,如果名为 OrderBy 的标志为 1,那么它是一个日历事件,我需要检查两个日期时间字段之间的范围.而所有其他类型我们只检查您正在查看的日期.我研究了 if 语句,并看到许多建议使用案例的帖子,因此我尝试将其实现到我的查询中.我的查询需要 where 的条件.我知道我有语法问题,这就是为什么我在这里希望有人能指出正确的方法.

I have a query that if a flag called OrderBy is 1 then it is a calendar event and I need to check for a range between two date time fields. Whereas all other types we just check for the day you are viewing. I research if statements and saw many posts where it was suggested a case be used so I tried to implement it into my query. My query needs the condition in the where. I know I have syntax issues and that is why I am here in the hopes that someone could point out the correct way to do this.

感谢您的宝贵时间

我的查询目前

SELECT          activities.*, 
                activitytypes.orderby 
FROM            activities 
LEFT OUTER JOIN activitytypes 
ON              activities.typeid = activitytypes.typeid 
WHERE           activities.userid = 86 
AND             activities.typeid NOT IN ( 5, 
                                          10, 
                                          11, 
                                          12, 
                                          19 ) 
AND 
                CASE 
                                WHEN activities.orderby = 1 THEN activities.starttime >= '2013-08-26 04:00:00' 
                                AND             activities.endtime <= '2013-08-27 04:00:00' 
                                ELSE activities.activitydate = '2013-08-26' 
                                order BY        activitytypes.orderby, 
                                                activities.starttime

推荐答案

只要使用足够的括号,您就可以使用 ANDOR 来做到这一点.

You can do this with AND and OR as long as you use sufficient parentheses.

我还假设 activities.OrderBy 可以为空.如果不是这种情况,您可以删除空检查:

Also I'm assuming that activities.OrderBy can be null. If that's not the case you can remove the null check:

SELECT activities.*, 
       activitytypes.orderby 
FROM   activities 
       LEFT OUTER JOIN activitytypes 
                    ON activities.typeid = activitytypes.typeid 
WHERE  activities.userid = 86 
       AND activities.typeid NOT IN ( 5, 10, 11, 12, 19 ) 
       AND ( ( activities.orderby = 1 
               AND activities.starttime >= '2013-08-26 04:00:00' 
               AND activities.endtime <= '2013-08-27 04:00:00' ) 
              OR ( ( activities.orderby IS NULL 
                      OR activities.orderby != 1 ) 
                   AND activities.activitydate = '2013-08-26' ) ) 
ORDER  BY activitytypes.orderby, 
          activities.starttime 

或者,如果您仍想使用 CASE,您只需使用 END 关闭您的 CASE 语句,如下所示:

Alternatively, if you still want to use CASE, you just need to close your CASE statement using END, like this:

SELECT          activities.*, 
                activitytypes.orderby 
FROM            activities 
LEFT OUTER JOIN activitytypes 
ON              activities.typeid = activitytypes.typeid 
WHERE           activities.userid = 86 
AND             activities.typeid NOT IN ( 5, 10, 11, 12, 19 ) 
AND             ( 
                  CASE 
                  WHEN activities.orderby = 1 THEN
                    activities.starttime >= '2013-08-26 04:00:00' AND activities.endtime <= '2013-08-27 04:00:00'
                  ELSE
                    activities.activitydate = '2013-08-26' 
                  END
                ) 
ORDER BY        activitytypes.orderby, 
                activities.starttime

这篇关于MYSQL where 子句中的条件的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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