Windows Batch,如何删除第一行和最后一行并保存为新的文本文件 [英] Windows Batch, how to remove first line and last line and save as a new text file
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问题描述
text1.txt
20150716
aaaa
bbbb
cccc
dddd
END
我想删除 20150716,然后整个文本将向上移动 1 行并删除最后一个特定的字符串END".最后,另存为名为 text1_copy.txt 的新文件.然后,文件变为:
I would like to remove 20150716, then the whole text will move up by 1 line and remove the last particular string "END". Finally, save as a new file called text1_copy.txt. Then, file becomes:
aaaa
bbbb
cccc
dddd
有什么想法吗?谢谢.
推荐答案
这只是跳过第一行,不写最后一行.
This just skips the first line and does not write the last one.
@echo off
setlocal enableextensions disabledelayedexpansion
for %%a in ("text1.txt") do > "%%~dpna_copy%%~xa" (
set "line="
for /f "skip=1 tokens=* delims=0123456789" %%a in ('
findstr /n /r "^" "%%a"
') do (
if defined line (
setlocal enabledelayedexpansion
echo(!line:~1!
endlocal
)
set "line=%%a"
)
)
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