R:创建函数以随机替换数据框中的数据 [英] R: Creating a Function to Randomly Replace Data from a Data Frame
问题描述
我正在使用R编程语言。假设我有以下数据(";my_data";):
set.seed(123)
num_var_1 <- rnorm(1000, 10, 1)
num_var_2 <- rnorm(1000, 10, 5)
num_var_3 <- rnorm(1000, 10, 10)
num_var_4 <- rnorm(1000, 10, 10)
num_var_5 <- rnorm(1000, 10, 10)
factor_1 <- c("A","B", "C")
factor_2 <- c("AA","BB", "CC")
factor_3 <- c("AAA","BBB", "CCC", "DDD")
factor_4 <- c("AAAA","BBBB", "CCCC", "DDDD", "EEEE")
factor_5 <- c("AAAAA","BBBBB", "CCCCC", "DDDDD", "EEEEE", "FFFFFF")
factor_var_1 <- as.factor(sample(factor_1, 1000, replace=TRUE, prob=c(0.3, 0.5, 0.2)))
factor_var_2 <- as.factor(sample(factor_2, 1000, replace=TRUE, prob=c(0.5, 0.3, 0.2)))
factor_var_3 <- as.factor(sample(factor_3, 1000, replace=TRUE, prob=c(0.5, 0.2, 0.2, 0.1)))
factor_var_4 <- as.factor(sample(factor_4, 1000, replace=TRUE, prob=c(0.5, 0.2, 0.1, 0.1, 0.1)))
factor_var_5 <- as.factor(sample(factor_4, 1000, replace=TRUE, prob=c(0.3, 0.2, 0.1, 0.1, 0.1)))
id = 1:1000
my_data = data.frame(id,num_var_1, num_var_2, num_var_3, num_var_4, num_var_5, factor_var_1, factor_var_2, factor_var_3, factor_var_4, factor_var_5)
> head(my_data)
id num_var_1 num_var_2 num_var_3 num_var_4 num_var_5 factor_var_1 factor_var_2 factor_var_3 factor_var_4 factor_var_5
1 1 9.439524 5.021006 4.883963 8.496925 11.965498 B AA AAA CCCC AAAA
2 2 9.769823 4.800225 12.369379 6.722429 16.501132 B AA AAA AAAA AAAA
3 3 11.558708 9.910099 4.584108 -4.481653 16.710042 C AA BBB AAAA CCCC
4 4 10.070508 9.339124 22.192276 3.027154 -2.841578 B CC DDD BBBB AAAA
5 5 10.129288 -2.746714 11.741359 35.984902 -10.261096 B AA AAA DDDD DDDD
6 6 11.715065 15.202867 3.847317 9.625850 32.053261 B AA CCC BBBB EEEE
我的问题:给定上述数据集,我正在尝试创建一个函数,以如下方式(重复地)从上述数据集中删除随机行:
第1步:数据集有10个变量-在第1步中,从这些变量中随机选择(&q;n&q;必须小于10)。
第2步:对于上述因素变量,如果它们是因素变量,则为每个因素变量随机选择级别的子集(大小为m)。对于每个非因素变量,在其最小值和最大值之间的某个点(称为该点)随机拆分它们。
第三步:生成一个介于0和1之间的随机数(称之为&q;r&q;)。
第4步:选择第2步中标识的所有行。对于这些行,请考虑逻辑条件中未使用的列。对于这些列,这些行中的任何元素都可以替换为0的概率为%(&q;r&q;)。
第5步:重复第1步到第4步10次。
作为示例,如下所示:
第一步:假设n被随机选择为4。选择4个随机变量:num_var_2、num_var_5、factor_var_3、factor_var_4
第二步:对于num_var_2,选择7处的点。对于num_var_5,选择19处的点。对于因子_var_3,有2个选定级别:";bbb";和";ccc";。对于因子_var_4,三个级别:AAAA、DDDD、EEEE。
第三步:随机选择0.25
第四步:
SELECT * FROM my_table WHERE num_var_2 >7 & num_var_5 > 19 & factor_var_3 = "BBB, CCC" & factor_var_4 = "AAAA, DDDD, EEEE"
。对于未选择的列中的每一行(num_var_1、num_var_3、num_var_4、factor_var_1、factor_var_2、factor_var_5),该行中的每个元素现在都有25%的机会被替换为0。第5步:重复第1步到第4步,重复10次。在某些情况下,可能会选择过去已被0替换的行。这不会有任何差异,因为用0替换0仍然是0。
有人能教我如何编写执行此操作的函数吗?
目前,我正在尝试手动完成此操作:
# 4 variables are selected
n = sample.int(10, 1)
[1] 4
# which 4 variables are selected (each number corresponds to their position):
sample.int(10, length(n))
[1] 6 2 1 4
num_var_1
num_var_2
num_var_4
factor_var_1
#select random points for the continuous variables
p1 <- runif(1, min(num_var_1), max(num_var_1))
p2 <- runif(1, min(num_var_2), max(num_var_2))
p4 <- runif(1, min(num_var_4), max(num_var_4))
#select random factor levels for the factor variable
nlevel = nlevels(factor_var_1)
nlevels = sample.int(nlevel, 1)
[1] 2
sample(factor_1, nlevels, replace=TRUE, prob=c(0.3, 0.5, 0.2))
[1] "A" "B"
#generate random probability number
r = runif(1,0,1)
[1] 0.4514667
#identify rows matching the above condition
identified_rows = my_data[which(my_data$num_var_1 > p1 & my_data$num_var_2 > p2 & my_data$num_var_4 > p4 & my_data$factor_var_1 %in% c("A", "B")), ]
> identified_rows
id num_var_1 num_var_2 num_var_3 num_var_4 num_var_5 factor_var_1 factor_var_2 factor_var_3 factor_var_4 factor_var_5
208 208 9.405383 15.53998 4.348425 29.87149 23.46945 B CC BBB DDDD DDDD
589 589 10.582991 18.84683 5.437036 31.53734 11.16494 B BB AAA BBBB CCCC
现在,对于行208,其余6列(num_var_3、num_var_5、factor_var_2、factor_var_3、factor_var_4、factor_var_5)中的值有0.4514667
将被替换为0的概率。对于第589行,剩余6列(num_var_3、num_var_5、factor_var_2、factor_var_3、factor_var_4、factor_var_5)中的任何一列中的值都有0.4514667
替换为0的可能性。
之后,我会再次将整个过程重复9次。
这是一个很长的方法--有人能帮我写一个函数来加快这个过程(例如,重复100次)吗?
谢谢!
推荐答案
这里有一个解决方案(我认为)。以下函数实现您上面概述的5步流程。
random_drop <- function(x) {
# Randomly select variables
which_vars <- names(x[, sort(sample(ncol(x), sample(ncol(x), 1)))])
# Randomly select factor levels subset or generate continuous cutoff value
cutoff_vals <- lapply(
which_vars,
function(i) {
if (is.factor(x[[i]])) {
return(sample(levels(x[[i]]), sample(nlevels(x[[i]]), 1)))
}
runif(1, min(x[[i]], na.rm = TRUE), max(x[[i]], na.rm = TRUE))
}
)
names(cutoff_vals) <- which_vars
# Create random prob value
r <- runif(1,0,1)
# Generate idx for which rows to select
row_idx <- Reduce(
`&`,
lapply(
which_vars,
function(i) {
if (is.factor(x[[i]])) {
return(x[[i]] %in% cutoff_vals[[i]])
}
x[[i]] > cutoff_vals[[i]]
}
)
)
x_sub <- x[row_idx, !colnames(x) %in% which_vars, drop = FALSE]
# With prob. 'r' fill row values in with '0'
r_mat <- matrix(
sample(
c(TRUE, FALSE),
ncol(x_sub)*nrow(x_sub),
replace = TRUE,
prob = c(r, 1 - r)
),
nrow = nrow(x_sub),
ncol = ncol(x_sub)
)
x_sub[r_mat] <- 0
x[row_idx, !colnames(x) %in% which_vars] <- x_sub
return(x)
}
然后,此函数将递归地应用该函数任意多次。
random_drop_recurse <- function(x, n = 10) {
if (n == 1) return(random_drop(x))
random_drop_recurse(random_drop(x), n = n - 1)
}
注意:0
不是有效的因子级别,因此此函数将因尝试用0
替换因子值而生成警告,并将用NA
替换因子值。
使用上面提供的数据子集,该函数分别运行10次和100次:
set.seed(123)
num_var_1 <- rnorm(1000, 10, 1)
num_var_2 <- rnorm(1000, 10, 5)
num_var_3 <- rnorm(1000, 10, 10)
num_var_4 <- rnorm(1000, 10, 10)
num_var_5 <- rnorm(1000, 10, 10)
factor_1 <- c("A","B", "C")
factor_2 <- c("AA","BB", "CC")
factor_3 <- c("AAA","BBB", "CCC", "DDD")
factor_4 <- c("AAAA","BBBB", "CCCC", "DDDD", "EEEE")
factor_5 <- c("AAAAA","BBBBB", "CCCCC", "DDDDD", "EEEEE", "FFFFFF")
factor_var_1 <- as.factor(sample(factor_1, 1000, replace=TRUE, prob=c(0.3, 0.5, 0.2)))
factor_var_2 <- as.factor(sample(factor_2, 1000, replace=TRUE, prob=c(0.5, 0.3, 0.2)))
factor_var_3 <- as.factor(sample(factor_3, 1000, replace=TRUE, prob=c(0.5, 0.2, 0.2, 0.1)))
factor_var_4 <- as.factor(sample(factor_4, 1000, replace=TRUE, prob=c(0.5, 0.2, 0.1, 0.1, 0.1)))
factor_var_5 <- as.factor(sample(factor_4, 1000, replace=TRUE, prob=c(0.3, 0.2, 0.1, 0.1, 0.1)))
my_data = data.frame(num_var_1, num_var_2, num_var_3, num_var_4, num_var_5, factor_var_1, factor_var_2, factor_var_3, factor_var_4, factor_var_5)
random_drop <- function(x) {
# Randomly select variables
which_vars <- names(x[, sort(sample(ncol(x), sample(ncol(x), 1)))])
# Randomly select factor levels subset or generate continuous cutoff value
cutoff_vals <- lapply(
which_vars,
function(i) {
if (is.factor(x[[i]])) {
return(sample(levels(x[[i]]), sample(nlevels(x[[i]]), 1)))
}
runif(1, min(x[[i]], na.rm = TRUE), max(x[[i]], na.rm = TRUE))
}
)
names(cutoff_vals) <- which_vars
# Create random prob value
r <- runif(1,0,1)
# Generate idx for which rows to select
row_idx <- Reduce(
`&`,
lapply(
which_vars,
function(i) {
if (is.factor(x[[i]])) {
return(x[[i]] %in% cutoff_vals[[i]])
}
x[[i]] > cutoff_vals[[i]]
}
)
)
x_sub <- x[row_idx, !colnames(x) %in% which_vars, drop = FALSE]
# With prob. 'r' fill row values in with '0'
r_mat <- matrix(
sample(
c(TRUE, FALSE),
ncol(x_sub)*nrow(x_sub),
replace = TRUE,
prob = c(r, 1 - r)
),
nrow = nrow(x_sub),
ncol = ncol(x_sub)
)
x_sub[r_mat] <- 0
x[row_idx, !colnames(x) %in% which_vars] <- x_sub
return(x)
}
random_drop_recurse <- function(x, n = 10) {
if (n == 1) return(random_drop(x))
random_drop_recurse(random_drop(x), n = n - 1)
}
suppressWarnings(
head(
random_drop_recurse(my_data[, c(1:3, 6:8)], 10),
20
)
)
#> num_var_1 num_var_2 num_var_3 factor_var_1 factor_var_2 factor_var_3
#> 1 9.439524 5.021006 4.883963 B AA AAA
#> 2 9.769823 4.800225 12.369379 B AA AAA
#> 3 11.558708 9.910099 0.000000 C AA BBB
#> 4 10.070508 9.339124 22.192276 B CC DDD
#> 5 10.129288 -2.746714 11.741359 B AA AAA
#> 6 11.715065 15.202867 3.847317 <NA> AA CCC
#> 7 10.460916 11.248629 -8.068930 C CC <NA>
#> 8 8.734939 22.081037 0.000000 C AA BBB
#> 9 9.313147 13.425991 30.460189 C AA BBB
#> 10 9.554338 7.765203 4.392376 B AA AAA
#> 11 11.224082 23.986956 1.640007 A <NA> AAA
#> 12 10.359814 24.161130 16.529475 A AA AAA
#> 13 0.000000 3.906441 0.000000 A CC <NA>
#> 14 10.110683 12.345160 17.516291 B CC AAA
#> 15 9.444159 8.943765 7.220249 A AA DDD
#> 16 11.786913 10.935256 21.226542 B CC DDD
#> 17 10.497850 11.137714 -1.726089 B AA AAA
#> 18 8.033383 3.690498 9.511232 B CC CCC
#> 19 10.701356 11.427948 2.958597 B BB AAA
#> 20 9.527209 18.746237 16.807586 C AA BBB
suppressWarnings(
head(
random_drop_recurse(my_data[, c(1:3, 6:8)], 100),
20
)
)
#> num_var_1 num_var_2 num_var_3 factor_var_1 factor_var_2 factor_var_3
#> 1 9.439524 0.00000 0.000000 B <NA> <NA>
#> 2 9.769823 0.00000 12.369379 B <NA> <NA>
#> 3 11.558708 0.00000 0.000000 <NA> <NA> BBB
#> 4 10.070508 0.00000 0.000000 B <NA> <NA>
#> 5 10.129288 0.00000 0.000000 B <NA> <NA>
#> 6 11.715065 0.00000 0.000000 B <NA> <NA>
#> 7 10.460916 0.00000 0.000000 C <NA> <NA>
#> 8 0.000000 22.08104 0.000000 <NA> AA <NA>
#> 9 9.313147 0.00000 0.000000 C <NA> <NA>
#> 10 0.000000 0.00000 0.000000 B AA AAA
#> 11 11.224082 0.00000 0.000000 <NA> <NA> AAA
#> 12 10.359814 0.00000 0.000000 A <NA> <NA>
#> 13 10.400771 0.00000 0.000000 A <NA> <NA>
#> 14 10.110683 0.00000 0.000000 B <NA> <NA>
#> 15 9.444159 0.00000 0.000000 A <NA> <NA>
#> 16 11.786913 0.00000 0.000000 B <NA> <NA>
#> 17 10.497850 0.00000 0.000000 B <NA> <NA>
#> 18 8.033383 0.00000 0.000000 B <NA> <NA>
#> 19 0.000000 0.00000 2.958597 B BB AAA
#> 20 9.527209 0.00000 0.000000 C <NA> BBB
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