指针数组的重载删除[] [英] overload delete[] for array of pointers
本文介绍了指针数组的重载删除[]的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我为代码搜索重载Delete[]的运算符或合适的析构函数的方法:
#include <iostream>
#include <string>
using namespace std;
class A {
private:
string name;
public:
A(string name){
this->name=name;
};
~A(){
cout<<"Destructor. Destroyed "<<name<<"
";
};
void operator delete(void* p, A* a){
cout<<"-Delete "<<a->name<<"
";
};
void operator delete(void* pointer){
cout<<"Delete"<<"
";
};
void operator delete[](void* pointer){
cout<<"Delete[]"<<"
";
};
};
int main(){
int number = 5;
A** a = new A* [ number ];
delete [] a;
system("pause");
return 0;
};
但是,无论我尝试什么,每次都会从文件delete2.cpp启动默认的删除[]。我做错了什么?
[已添加]添加了重载删除[]的尝试。
推荐答案
您的代码不是创建或销毁A的实例,而是指向它的指针。
#include <iostream>
#include <string>
using namespace std;
class A {
private:
string name;
public:
A() {}
A(string name){
this->name=name;
};
~A(){
cout<<"Destructor. Destroyed "<<name<<"
";
};
void operator delete(void* p, A* a){
cout<<"-Delete "<<a->name<<"
";
};
void operator delete(void* pointer){
cout<<"Delete"<<"
";
};
void operator delete[](void* pointer){
cout<<"Delete[]"<<"
";
};
};
int main(){
int number = 5;
A* a = new A[ number ];
delete [] a;
system("pause");
return 0;
};
如期调用运算符[]:http://ideone.com/EuS3Hi
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