Discord.js不执行客户端。打开(&Q;消息&Q;) [英] Discord.js don't execute client.on("message")
本文介绍了Discord.js不执行客户端。打开(&Q;消息&Q;)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试使用discord.js和NodeJS来构建一个不一致的机器人,但我遇到了一个问题。当我运行代码时,dicord.js不执行client.on(";message";),,他只是跳过这一部分,转到代码的末尾,如下图所示:
index.js
const { Client, Intents } = require('discord.js');
const { prefix, token } = require("./config.json");
require('dotenv').config();
const client = new Client({ intents: [Intents.FLAGS.GUILDS] });
const queue = new Map();
client.once("ready", c => {
console.log(`🚀 [${c.user.tag}] Running...`);
client.user.setActivity(`${prefix}play`, { type: "PLAYING" })
});
client.once("reconnecting", c => {
console.log(`🔃 [${c.user.tag}] Reconnecting...`);
});
client.once("disconnect", c => {
console.log(`[${c.user.tag}] Disconnect!`);
});
client.on("message", async message => {
console.log("I'm here!")
if (message.author.bot) return;
if (!message.content.startsWith(prefix)) return;
const serverQueue = queue.get(message.guild.id);
if (message.content.startsWith(`${prefix}play`)) {
execute(message, serverQueue);
return;
} else if (message.content.startsWith(`${prefix}skip`)) {
skip(message, serverQueue);
return;
} else if (message.content.startsWith(`${prefix}stop`)) {
stop(message, serverQueue);
return;
} else {
message.channel.send("You need to enter a valid command!");
}
});
async function execute(message, serverQueue) {
const args = message.content.split(" ");
const voiceChannel = message.member.voice.channel;
if (!voiceChannel)
return message.channel.send(
"You need to be in a voice channel to play music!"
);
const permissions = voiceChannel.permissionsFor(message.client.user);
if (!permissions.has("CONNECT") || !permissions.has("SPEAK")) {
return message.channel.send(
"I need the permissions to join and speak in your voice channel!"
);
}
const songInfo = await ytdl.getInfo(args[1]);
const song = {
title: songInfo.videoDetails.title,
url: songInfo.videoDetails.video_url,
};
if (!serverQueue) {
const queueContruct = {
textChannel: message.channel,
voiceChannel: voiceChannel,
connection: null,
songs: [],
volume: 5,
playing: true
};
queue.set(message.guild.id, queueContruct);
queueContruct.songs.push(song);
try {
var connection = await voiceChannel.join();
queueContruct.connection = connection;
play(message.guild, queueContruct.songs[0]);
} catch (err) {
console.log(err);
queue.delete(message.guild.id);
return message.channel.send(err);
}
} else {
serverQueue.songs.push(song);
return message.channel.send(`${song.title} has been added to the queue!`);
}
}
function skip(message, serverQueue) {
if (!message.member.voice.channel)
return message.channel.send(
"You have to be in a voice channel to stop the music!"
);
if (!serverQueue)
return message.channel.send("There is no song that I could skip!");
serverQueue.connection.dispatcher.end();
}
function stop(message, serverQueue) {
if (!message.member.voice.channel)
return message.channel.send(
"You have to be in a voice channel to stop the music!"
);
if (!serverQueue)
return message.channel.send("There is no song that I could stop!");
serverQueue.songs = [];
serverQueue.connection.dispatcher.end();
}
function play(guild, song) {
const serverQueue = queue.get(guild.id);
if (!song) {
serverQueue.voiceChannel.leave();
queue.delete(guild.id);
return;
}
const dispatcher = serverQueue.connection
.play(ytdl(song.url))
.on("finish", () => {
serverQueue.songs.shift();
play(guild, serverQueue.songs[0]);
})
.on("error", error => console.error(error));
dispatcher.setVolumeLogarithmic(serverQueue.volume / 5);
serverQueue.textChannel.send(`Start playing: **${song.title}**`);
}
client.login(token);
您能帮助解决此问题吗?
推荐答案
虽然message
事件确实已弃用,但您在使用它时仍应收到进程警告。
主要问题是你没有添加工会消息的意图,你的机器人不能看到消息。将Intents.FLAGS.GUILD_MESSAGES
添加到您的客户端意图。
const client = new Client({ intents: [Intents.FLAGS.GUILDS, Intents.FLAGS.GUILD_MESSAGES] });
这篇关于Discord.js不执行客户端。打开(&Q;消息&Q;)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
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