Discord.js不执行客户端。打开(&Q;消息&Q;) [英] Discord.js don't execute client.on("message")

查看:0
本文介绍了Discord.js不执行客户端。打开(&Q;消息&Q;)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用discord.jsNodeJS来构建一个不一致的机器人,但我遇到了一个问题。当我运行代码时,dicord.js不执行client.on(";message";),,他只是跳过这一部分,转到代码的末尾,如下图所示:

index.js

    const { Client, Intents } = require('discord.js');
const { prefix, token } = require("./config.json");
require('dotenv').config();

const client = new Client({ intents: [Intents.FLAGS.GUILDS] });

const queue = new Map();

client.once("ready", c => {
  console.log(`🚀 [${c.user.tag}] Running...`);
  client.user.setActivity(`${prefix}play`, { type: "PLAYING" })
});

client.once("reconnecting", c => {
  console.log(`🔃 [${c.user.tag}] Reconnecting...`);
});

client.once("disconnect", c => {
  console.log(`[${c.user.tag}] Disconnect!`);
});


client.on("message", async message => {
  console.log("I'm here!")
  if (message.author.bot) return;
  if (!message.content.startsWith(prefix)) return;

  const serverQueue = queue.get(message.guild.id);

  if (message.content.startsWith(`${prefix}play`)) {
    execute(message, serverQueue);
    return;
  } else if (message.content.startsWith(`${prefix}skip`)) {
    skip(message, serverQueue);
    return;
  } else if (message.content.startsWith(`${prefix}stop`)) {
    stop(message, serverQueue);
    return;
  } else {
    message.channel.send("You need to enter a valid command!");
  }
});

async function execute(message, serverQueue) {
  const args = message.content.split(" ");

  const voiceChannel = message.member.voice.channel;
  if (!voiceChannel)
    return message.channel.send(
      "You need to be in a voice channel to play music!"
    );
  const permissions = voiceChannel.permissionsFor(message.client.user);
  if (!permissions.has("CONNECT") || !permissions.has("SPEAK")) {
    return message.channel.send(
      "I need the permissions to join and speak in your voice channel!"
    );
  }

  const songInfo = await ytdl.getInfo(args[1]);
  const song = {
        title: songInfo.videoDetails.title,
        url: songInfo.videoDetails.video_url,
   };

  if (!serverQueue) {
    const queueContruct = {
      textChannel: message.channel,
      voiceChannel: voiceChannel,
      connection: null,
      songs: [],
      volume: 5,
      playing: true
    };

    queue.set(message.guild.id, queueContruct);

    queueContruct.songs.push(song);

    try {
      var connection = await voiceChannel.join();
      queueContruct.connection = connection;
      play(message.guild, queueContruct.songs[0]);
    } catch (err) {
      console.log(err);
      queue.delete(message.guild.id);
      return message.channel.send(err);
    }
  } else {
    serverQueue.songs.push(song);
    return message.channel.send(`${song.title} has been added to the queue!`);
  }
}

function skip(message, serverQueue) {
  if (!message.member.voice.channel)
    return message.channel.send(
      "You have to be in a voice channel to stop the music!"
    );
  if (!serverQueue)
    return message.channel.send("There is no song that I could skip!");
  serverQueue.connection.dispatcher.end();
}

function stop(message, serverQueue) {
  if (!message.member.voice.channel)
    return message.channel.send(
      "You have to be in a voice channel to stop the music!"
    );
    
  if (!serverQueue)
    return message.channel.send("There is no song that I could stop!");
    
  serverQueue.songs = [];
  serverQueue.connection.dispatcher.end();
}

function play(guild, song) {
  const serverQueue = queue.get(guild.id);
  if (!song) {
    serverQueue.voiceChannel.leave();
    queue.delete(guild.id);
    return;
  }

  const dispatcher = serverQueue.connection
    .play(ytdl(song.url))
    .on("finish", () => {
      serverQueue.songs.shift();
      play(guild, serverQueue.songs[0]);
    })
    .on("error", error => console.error(error));
  dispatcher.setVolumeLogarithmic(serverQueue.volume / 5);
  serverQueue.textChannel.send(`Start playing: **${song.title}**`);
}

client.login(token);

您能帮助解决此问题吗?

推荐答案

虽然message事件确实已弃用,但您在使用它时仍应收到进程警告。

主要问题是你没有添加工会消息的意图,你的机器人不能看到消息。将Intents.FLAGS.GUILD_MESSAGES添加到您的客户端意图。

const client = new Client({ intents: [Intents.FLAGS.GUILDS, Intents.FLAGS.GUILD_MESSAGES] });

这篇关于Discord.js不执行客户端。打开(&Q;消息&Q;)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆