限制双到小数点后两位 [英] Limit a double to two decimal places

问题描述

我如何实现从双下面的转换为字符串：

  1.4324 =＆GT; 1.43
9.4000 =＆GT; 9.4
43.000 =＆GT; 43
 

即。我要四舍五入到的小数位数，但不希望任何尾随零，也就是我不想

  9.4 =＆GT; 9.40（错）
43.000 =＆GT; 43.00（错）
 

所以这code，我现在不工作，因为它显示多余的零：

  [的NSString stringWithFormat：@％2F，总]
 

解决方案

使用<一个href=\"http://developer.apple.com/documentation/Cocoa/Reference/Foundation/Classes/NSNumberFormatter%5FClass/\">NSNumberFormatter.见的格式化编程指南上<一章href=\"http://developer.apple.com/documentation/Cocoa/Conceptual/DataFormatting/Articles/dfNumberFormatting10%5F4.html\">Number格式化的。

How do I achieve the following conversion from double to a string:

1.4324 => "1.43"
9.4000 => "9.4"
43.000 => "43"

i.e. I want to round to to decimal places but dont want any trailing zeros, ie i dont want

9.4 => "9.40" (wrong)
43.000 => "43.00" (wrong)

So this code which I have now doesn't work as it displays excess zeros:

[NSString stringWithFormat: @"%.2f", total]

解决方案

Use NSNumberFormatter. See the Data Formatting Programming Guide's chapter on Number Formatters.

这篇关于限制双到小数点后两位的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！