随机浮点数 [英] Random float number
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问题描述
我写了这个函数来得到0之间的伪随机浮动。1包括:
浮动randomFloat()
{
浮动R =(浮点)兰特()/(浮点)RAND_MAX;
返回ř;
}
然而,它总是返回0.563585。同一号码无论多少次,我跑我的控制台应用程序。
编辑:
如果需要的话这是我的整个应用程序:
的#include<&stdio.h中GT;
#包括LT&;&stdlib.h中GT;浮动randomFloat()
{
浮动R =(浮点)兰特()/(浮点)RAND_MAX;
返回ř;
}INT主(INT ARGC,CHAR *的argv [])
{
浮X [] = {
0.72,0.91,0.46,0.03,0.12,0.96,0.79,0.46,0.66,0.72,0.35,-0.16,
-0.04,-0.11,0.31,0.00,-0.43,0.57,-0.47,-0.72,-0.57,-0.25,
0.47,-0.12,-0.58,-0.48,-0.79,-0.42,-0.76,-0.77
}; 浮Y [] = {
0.82,-0.69,0.80,0.93,0.25,0.47,-0.75,0.98,0.24,-0.15,0.01,
0.84,0.68,0.10,-0.96,-0.26,-0.65,-0.97,-0.03,-0.64,0.15,-0.43,
-0.88,-0.90,0.62,0.05,-0.92,-0.09,0.65,-0.76
}; INT输出[] = {
-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,
1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1
}; INT patternCount = sizeof的(X)/的sizeof(int);在 浮动权重[2];
权重[0] = randomFloat();
权重[1] = randomFloat(); 的printf(%F \\ N,权重[1]); 浮learningRate = 0.1; 系统(暂停);
返回0;
}
解决方案
您需要调用
函数srand(时间(NULL));
使用前兰特
首次。 时间
是< time.h中方式>
编辑:正如乔纳森·莱弗勒指出,这是很容易predicted,所以不要尝试使用它的cryprography
I wrote this function to get a pseudo random float between 0 .. 1 inclusive:
float randomFloat()
{
float r = (float)rand()/(float)RAND_MAX;
return r;
}
However, it is always returning 0.563585. The same number no matter how many times I run my console application.
EDIT:
Here is my entire application if needed:
#include <stdio.h>
#include <stdlib.h>
float randomFloat()
{
float r = (float)rand() / (float)RAND_MAX;
return r;
}
int main(int argc, char *argv[])
{
float x[] = {
0.72, 0.91, 0.46, 0.03, 0.12, 0.96, 0.79, 0.46, 0.66, 0.72, 0.35, -0.16,
-0.04, -0.11, 0.31, 0.00, -0.43, 0.57, -0.47, -0.72, -0.57, -0.25,
0.47, -0.12, -0.58, -0.48, -0.79, -0.42, -0.76, -0.77
};
float y[] = {
0.82, -0.69, 0.80, 0.93, 0.25, 0.47, -0.75, 0.98, 0.24, -0.15, 0.01,
0.84, 0.68, 0.10, -0.96, -0.26, -0.65, -0.97, -0.03, -0.64, 0.15, -0.43,
-0.88, -0.90, 0.62, 0.05, -0.92, -0.09, 0.65, -0.76
};
int outputs[] = {
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1
};
int patternCount = sizeof(x) / sizeof(int);
float weights[2];
weights[0] = randomFloat();
weights[1] = randomFloat();
printf("%f\n", weights[1]);
float learningRate = 0.1;
system("PAUSE");
return 0;
}
解决方案
You need to call
srand(time(NULL));
before using rand
for the first time. time
is in <time.h>
.
EDIT: As Jonathan Leffler points out, this is easily predicted, so don't try using it for cryprography.
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