是用C默认长整型诠释？ [英] is int by default long int in C?

问题描述

为什么说我发现int和long int的长度都显示为4个字节？难道int是默认长整型？

解决方案

 的sizeof（短）＆LT; = sizeof的（INT）＆LT; = sizeof的（长）
 

这就是你可以指望。剩下的就是完全取决于执行。在DOS下的昔日，16位编译器通常的sizeof（int）的==的sizeof（短）== 2.在32位系统上，的sizeof（INT）通常等于sizeof（长）== 4.作为一项规则拇指， INT 是处理器能以最快的工作类型。无例外无规律...

编辑：删除了第二条规则，的sizeof（短）LT;的sizeof（长），这是不是C标准的一部分。在一些平台上，的sizeof（短）可能实际上是等于的sizeof（长）。

Why is it that I'm finding the size of int and long int are shown to be 4 bytes? Is it that the int is by default long int?

解决方案

sizeof(short) <= sizeof(int) <= sizeof(long)

That's all you can count on. The rest is completely up to the implementation. In the olden days of DOS, 16 bit compilers usually has sizeof(int) == sizeof(short) == 2. On 32 bit systems, sizeof(int) is usually equal to sizeof(long) == 4. As a rule of thumb, int is the type the processor can work with the fastest. No rule without exceptions...

EDIT: Removed the second rule, sizeof(short) < sizeof(long), which is NOT part of the C standard. On some platforms, sizeof(short) may actually be equal to sizeof(long).

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