为什么我不能从一个Ajax函数返回的responseText？ [英] Why can I not return responseText from an Ajax function?

问题描述

下面是我的Ajax功能的一部分。出于某种原因，我想不通，我可以的警报（）的的responseText，但不能的返回的的responseText。任何人都可以帮忙吗？我需要在另一功能中使用该值。

  http.onreadystatechange =功能（）{
    如果（http.readyState == 4和＆安培; http.status == 200）{
        返回http.responseText;
    }
}
 

解决方案

您将无法处理，你是从你的异步回调返回的返回值。您应该直接处理的responseText 中的回调，或致电一个辅助函数来处理响应：

  http.onreadystatechange =功能（）{
    如果（http.readyState == 4和＆安培; http.status == 200）{
        用handleResponse（http.responseText）;
    }
}

功能用handleResponse（响应）{
    警报（响应）;
}
 

Here is part of my Ajax function. For some reason that I cannot figure out, I am able to alert() responseText but not able to return responseText. Can anybody help? I need that value to be used in another function.

http.onreadystatechange = function(){
    if( http.readyState == 4 && http.status == 200 ){
        return http.responseText;
    }
}

解决方案

You will not be able to handle the return value that you are returning from your asynchronous callback. You should handle the responseText within the callback directly, or call a helper function to handle the response:

http.onreadystatechange = function () {
    if (http.readyState == 4 && http.status == 200) {
        handleResponse(http.responseText);
    }
}

function handleResponse (response) {
    alert(response);
}

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