颜色（int，int，int）和颜色（float，float，float）模糊调用 [英] Color(int, int, int) vs Color(float, float, float) ambiguous call

问题描述

如何解决C ++中这两者之间的模糊调用？

How can I resolve the ambiguous call between these two in C++?

Color（int，int，int）

Color（float，float，float）

这些值是硬编码的，即 Color（1,2,3），当它们是变量 Color（r，g，b）。为什么编译器不会根据数据类型解析？在变量形式？

It is both ambiguous when the values are hardcoded i.e. Color(1, 2, 3) and when they are variables Color(r, g, b). Why wouldn't the compiler resolve according to data type? In variable form?

编辑：
对不起，太多的C ++让我忘记有其他语言。

Sorry, too much C++ makes me forget there's a other languages. And there is not much "full code" that was all about it.

float x, y, z;
int r, g, b;
Color(1, 2, 3); // ambiguous
Color(1.0, 2.0, 3.0); // ambiguous
Color(r, g, b); // ambiguous  <--- this one is a real pain
Color((int)r, (int)g, (int)b); // ambiguous
Color(x, y, z); //OK
Color(1u, 2u, 3u); //OK
Color(1.0f, 2.0f, 3.0f); //OK

推荐答案

问题似乎是

Color(unsigned, unsigned, unsigned);
Color(float, float, float);

即，所有三个参数必须为 float 或 unsigned 。如果你尝试用其他类型（如 int 或 double ）调用它，不知道你想要什么，因为两者只是一个好的（或如果你喜欢坏）。你可以通过声明更多的重载来改进一些东西：

ie, all three args must be either float or unsigned. If you try to call it with other types (such as int or double), its ambiguous -- the compiler doesn't know which you want as both are just a good (or as bad if you prefer). You could improve things a bit by declaring more overloads:

Color(int, int, int);
Color(double, double, double);

但是如果尝试用混合类型调用它，您仍然会遇到模糊错误。

but you'd still get ambiguity errors if try to call it with mixed types.

这篇关于颜色（int，int，int）和颜色（float，float，float）模糊调用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！