bash如何处理嵌套引号? [英] How does bash deal with nested quotes?

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本文介绍了bash如何处理嵌套引号?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要运行一个带有这样语法的命令:

runuser -l userNameHere -c'/ path / to / command arg1 arg2'

I need to run a command with a syntax like this:
runuser -l userNameHere -c '/path/to/command arg1 arg2'

不幸的是,我必须在命令中嵌入额外的'字符,我不能告诉bash正确解释这些。我想运行的命令实际上是:

Unfortunately, I have to nest additional ' characters into the command itself and I can't tell bash to interpret these correctly. The command I would like to run is actually:

runuser -l miner -c'screen -S Mine -p 0 -X不幸的是,bash似乎正在击中第二个'




$ b $ code>和puking。这是错误:

-bash:screen -S Mine -p 0 -X eval stuff:没有这样的文件或目录,所以显然不是通过'

runuser -l miner -c 'screen -S Mine -p 0 -X eval 'stuff "pwd"\015''

Unfortunately, bash seems to be hitting the second ' and puking. This is the error:
-bash: screen -S Mine -p 0 -X eval stuff: No such file or directory, so obviously it's not getting past the '.

如何嵌套为一个命令?谢谢!

How can I nest this as one command? Thank you!

推荐答案

您可以使用 bash $'...'。这可以包含转义的单引号。

You can use another type of quoting supported by bash, $'...'. This can contain escaped single quotes.

runuser -l miner $'screen -S Mine -p 0 -X eval \'stuff "pwd"\015\''

请注意,在 $ '...',则会在代码点015处将 \015 替换为实际的ASCII字符,因此,如果这不是你想要的,你还需要转义反斜杠。

Note that within $'...', the \015 will be treated replaced with the actual ASCII character at codepoint 015, so if that's not what you want, you'll need to escape the backslash as well.

runuser -l miner $'screen -S Mine -p 0 -X eval \'stuff "pwd"\\015\''

可以利用 $'...'来删除 eval 的需要:

I think you can take advantage of the $'...' to remove the need for eval as well:

runuser -l miner $'screen -S Mine -p 0 -X stuff "pwd"\015'

这篇关于bash如何处理嵌套引号?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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