将一个数组中的对象属性与另一个数组中的对象属性进行比较 [英] comparing object attribute in one array to an object attribute in another array

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问题描述

我似乎在访问和比较目标c中的NSMutableArrays中的对象时遇到困难。
我很新,所以当解释时,一些代码会很好。
我有一个字符类和一个characterfound类。代码如下:

  @implementation character 

@synthesize IDE,name;

- (void)dealloc {
[text release];
[super dealloc];
}

@implementation characterfound

@synthesize IDE;

- (void)dealloc {
[text release];
[super dealloc];
}



我有两个数组用名称和id填充。
如果我想比较只是id的构建一个新的数组或做别的事情。
我如何做到这一点。



例如

 
* * character [] **
name:joe smith
IDE:ik321

name:james smith
IDE:ik32a

characterfound [] **

IDE:2343k
IDE:ik32a

二,id将被找到,我可以把名称放在另一个数组。
或输出它..



我会尝试解释我的问题,并更具体thnx回复btw。
我有两个类字符类

@interface字符:NSObject {
// attributes
NSInteger type;
NSInteger rep1,rep2,rep3,rep4,rep5;
NSString * name;
NSString * IDE;



}

和characterfound类




@interface characterfound:NSObject {
// attributes
// NSInteger IDE;
NSInteger类型;
NSString * IDE;



}



当我解析一个xml文件时遇到不同的标签并且这样填充我的字符类型



例如




也有一些其他的xml在foundcharacter如下:







所以我的第一个数组将填充字符对象包括它的属性
和第二个数组foundcharacter也将一样。
characterarray =
[character1 name =johnsonid =jfja33,character2 name =smithid =sdfae23]



characterfoundarray
[characterfound ide =jfja33,characterfound2 ide =jap234];

所以我的数组被填充对象及其属性

解决方案

如果按ID查找字符对象是一个常见的操作,你应该创建一个从id到字符对象的映射,此时从第二个数组进行查找将是微不足道的:

  NSMutableDictionary * charactersById = [NSMutableDictionary dictionary]; 
for(Character * character in characters){
[charactersById setObject:character forKey:[character IDE]];
}

(注意,我已经为你的类大写了示例代码;代码,因为编写忽略标准语言约定的代码在任何语言中都是一个坏主意;它会显着降低代码的可读性。)


i seem to be having difficulties in accessing and comparing objects in NSMutableArrays in objective c. I'm very new so when explaining , some code would be nice. I have a character class and a characterfound class. The code looks like this:

@implementation character

@synthesize IDE, name;

- (void) dealloc {
    [text release];
    [super dealloc];
}

@implementation characterfound

@synthesize IDE;

- (void) dealloc {
    [text release];
    [super dealloc];
}

I have two arrays which are being filled with names and id's. If I want to compare just the id's to build a new array or do something else with it. How do I do this.

for instance

**character[]**
name :joe smith
IDE: ik321

name :james smith
IDE: ik32a

**characterfound[]**

IDE:2343k
IDE:ik32a 

so when I compare the two ,the id will be found and I can put the name in another array. Or output it..

I'll try to refrase my question and be more specific thnx for replying btw. I have two classes the character class @interface character : NSObject { // attributes NSInteger type; NSInteger rep1, rep2, rep3, rep4, rep5; NSString *name; NSString *IDE;

} and the characterfound class

@interface characterfound : NSObject { // attributes //NSInteger IDE; NSInteger type; NSString *IDE;

}

When I'm parsing an xml file it encounters different tags and such and fills my characterclass accordingly

for instance

also there is some other xml in the foundcharacter like so:

so my first array will be filled with the character object including it's attributes and the second array foundcharacter will be as well. characterarray = [character1 name="johnson" id="jfja33", character2 name="smith" id="sdfae23"]

characterfoundarray [characterfound ide ="jfja33 , characterfound2 ide="jap234" ]; So my arrays are being filled with objects and their attributes and I would like to compare the attributes( if that's possible ) and create an output.

解决方案

If looking up character objects by ID is a common operation, you should create a mapping from id's to character objects, at which point doing the lookup from your second array will be trivial:

NSMutableDictionary* charactersById = [NSMutableDictionary dictionary];
for (Character* character in characters) {
    [charactersById setObject:character forKey:[character IDE]];
}

(Note that I've made your class upper-case for the example code; you should do the same in your code since writing code that ignores standard language conventions is a bad idea in any language; it significantly reduces the readability of your code.)

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