在查询中外部添加一个列 [英] Adding one more column externally in query
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问题描述
我有以下查询:
WITH ctablee(mon, [<=15], [<=18], [<=20], [>20])
AS
(SELECT *
FROM (SELECT CONVERT(CHAR(4), [Data OUT (No Val#Vuoto)], 100) mon, [Gruppi Min (GG Flusso/Decorrenza-->Out)],
Count([Gruppi Min (GG Flusso/Decorrenza-->Out)]) cnt
FROM dbpratiche
WHERE compagnia = 'GENERTEL'
GROUP BY [Gruppi Min (GG Flusso/Decorrenza-->Out)], CONVERT(CHAR(4), [Data OUT (No Val#Vuoto)], 100)
) T
PIVOT
(
sum(cnt)
FOR [Gruppi Min (GG Flusso/Decorrenza-->Out)] IN ([<=15], [<=18], [<=20], [>20])) p
)
SELECT mon, isnull([<=15], 0) [<=15], isnull([<=18], 0) [<=18], isnull([<=20], 0) [<=20], isnull([>20], 0) [>20], isnull([<=15] + [<=18] + [<=20] + [>20], 0) Total
FROM ctablee
这会导致:
>
通过以下查询添加一个列:
I wanted to add one more column in it which comes through following query:
select
AVG([Min (GG Flusso/Decorrenza-->Out) Cal#] ) avrage
from dbo.dbPratiche
where Compagnia='GENERTEL'
and Stato='OUT ATTIVATA'
group by convert(char(4),[Data OUT (No Val#Vuoto)],100)
:
>
我只想在第一个结果中使用此列(avrage)affter Total。
I just wanted to have this column (avrage) affter Total in first result.
如何将这两个查询
注意:两个查询生成的行相等。
Note: rows generated by both of the queries are equal.
推荐答案
我通过在内部连接表来做:
I done it by joining tables internally as:
WITH ctablee(mon, [<=15], [<=18], [<=20], [>20])
AS
(SELECT *
FROM (SELECT CONVERT(CHAR(4), [Data OUT (No Val#Vuoto)], 100) mon, [Gruppi Min (GG Flusso/Decorrenza-->Out)],
Count([Gruppi Min (GG Flusso/Decorrenza-->Out)]) cnt
FROM dbpratiche
WHERE compagnia = 'GENERTEL'
GROUP BY [Gruppi Min (GG Flusso/Decorrenza-->Out)], CONVERT(CHAR(4), [Data OUT (No Val#Vuoto)], 100)
) T
PIVOT
(
sum(cnt)
FOR [Gruppi Min (GG Flusso/Decorrenza-->Out)] IN ([<=15], [<=18], [<=20], [>20])) p
)
SELECT TB.mon, isnull(TB.[<=15], 0) [<=15], isnull(TB.[<=18], 0) [<=18], isnull(TB.[<=20], 0) [<=20], isnull(TB.[>20], 0) [>20], isnull(TB.[<=15] + TB.[<=18] + TB.[<=20] + TB.[>20], 0) Total
,
(
select
AVG(d.[Min (GG Flusso/Decorrenza-->Out) Cal#] ) avrage
from dbo.dbPratiche d,ctablee v
where
convert(char(4),d.[Data OUT (No Val#Vuoto)],100)=TB.mon and
d.Compagnia='GENERTEL'
and d.Stato='OUT ATTIVATA'
group by convert(char(4),d.[Data OUT (No Val#Vuoto)],100)) as 'TK'
FROM ctablee TB
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