Python格式的timedelta到字符串 [英] Python format timedelta to string

问题描述

我是一个Python新手（2周），我无法格式化一个 datetime.timedelta 对象。

I'm a Python newbie (2 weeks) and I'm having trouble formatting a datetime.timedelta object.

这是我要做的：
我有一个对象列表，该对象类的一个成员是一个timedelta对象，显示一个事件的持续时间。我想以小时：分钟的格式显示该持续时间。

Here's what I'm trying to do: I have a list of objects and one of the members of the class of the object is a timedelta object that shows the duration of an event. I would like to display that duration in the format of hours:minutes.

我已经尝试了各种各样的方法来做到这一点，我有困难。我目前的方法是为我的对象添加返回时间和分钟的方法。我可以通过将timedelta.seconds除以3600并舍入它来获得时间。我有麻烦得到余数秒，并将其转换为分钟。

I have tried a variety of methods for doing this and I'm having difficulty. My current approach is to add methods to the class for my objects that return hours and minutes. I can get the hours by dividing the timedelta.seconds by 3600 and rounding it. I'm having trouble with getting the remainder seconds and converting that to minutes.

顺便说一句，我使用 Google AppEngine 与 Django模板进行演示。

By the way, I'm using Google AppEngine with Django Templates for presentation.

如果有人可以帮助或知道更好的解决方法

If anyone can help or knows of a better way to resolve this, I would be very happy.

谢谢，

推荐答案

感谢大家的帮助。我把很多想法放在一起，让我知道你的想法。

Thanks everyone for your help. I took many of your ideas and put them together, let me know what you think.

我在课堂上添加了两种方法：

I added two methods to the class like this:

def hours(self):
    retval = ""
    if self.totalTime:
        hoursfloat = self.totalTime.seconds / 3600
        retval = round(hoursfloat)
    return retval

def minutes(self):
    retval = ""
    if self.totalTime:
        minutesfloat = self.totalTime.seconds / 60
        hoursAsMinutes = self.hours() * 60
        retval = round(minutesfloat - hoursAsMinutes)
    return retval

在我的django中，我使用了这个（sum是对象，它在一个字典中）：

In my django I used this (sum is the object and it is in a dictionary):

<td>{{ sum.0 }}</td>    
<td>{{ sum.1.hours|stringformat:"d" }}:{{ sum.1.minutes|stringformat:"#02.0d" }}</td>

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