将C#字符串解析为DateTime [英] Parse C# string to DateTime

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本文介绍了将C#字符串解析为DateTime的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个这样的字符串:
250920111414



我想从该字符串创建一个DateTime对象。到目前为止,我使用子串,这样做:

  string date = 250920111414; 

int year = Convert.ToInt32(date.Substring(4,4));
int month = Convert.ToInt32(date.Substring(2,2));
...
DateTime dt = new DateTime(年,月,日...);

是否可以使用字符串格式,做同样的,没有子字符串?

解决方案

绝对。从您的字符串中猜测格式,您可以使用 ParseExact

  string format =ddMMyyyyHHmm; 

DateTime dt = DateTime.ParseExact(value,format,CultureInfo.InvariantCulture);

TryParseExact

  DateTime dt; 
bool success = DateTime.TryParseExact(value,format,
CultureInfo.InvariantCulture,DateTimeStyles.None,out dt);

后一个调用将简单地返回 false 解析失败,而不是抛出异常 - 如果您可能有不良数据不应导致整个任务失败(例如,它是用户输入,并且您只想提示它们),那么这是一个更好的调用使用。 p>

编辑:有关格式字符串详细信息的详细信息,请参阅自定义日期和时间格式字符串


I have a string like this: 250920111414

I want to create a DateTime object from that string. As of now, I use substring and do it like this:

string date = 250920111414;

int year = Convert.ToInt32(date.Substring(4, 4));
int month = Convert.ToInt32(date.Substring(2, 2));
...
DateTime dt = new DateTime(year, month, day ...);

Is it possible to use string format, to do the same, without substring?

解决方案

Absolutely. Guessing the format from your string, you can use ParseExact

string format = "ddMMyyyyHHmm";

DateTime dt = DateTime.ParseExact(value, format, CultureInfo.InvariantCulture);

or TryParseExact:

DateTime dt;
bool success = DateTime.TryParseExact(value, format, 
                     CultureInfo.InvariantCulture, DateTimeStyles.None, out dt);

The latter call will simply return false on parse failure, instead of throwing an exception - if you may have bad data which shouldn't cause the overall task to fail (e.g. it's user input, and you just want to prompt them) then this is a better call to use.

EDIT: For more details about the format string details, see "Custom Date and Time Format Strings" in MSDN.

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