C＃泛型委托类型推断 [英] C# generic delegate type inference

问题描述

为什么C＃编译器在指定的示例中不能将T推断为int？

Why can't the C# compiler infer T to int in the specified example?

void Main()
{
    int a = 0;
    Parse("1", x => a = x);
    // Compiler error:
    // Cannot convert expression type 'int' to return type 'T'
}

public void Parse<T>(string x, Func<T, T> setter)
{
    var parsed = ....
    setter(parsed);
}

推荐答案

方法类型推理在lambda要求在推测出返回的类型之前，已经知道 lambda参数的类型。因此，例如，如果您有：

Method type inference on a lambda requires that the types of the lambda parameters be already known before the types of the returns are inferred. So for example if you had:

void M<A, B, C>(A a, Func<A, B> f1, Func<B, C> f2) { }

和一个电话

M(1, a=>a.ToString(), b=>b.Length);

然后我们会推断：

A is int, from the first argument
Therefore the second parameter is Func<int, B>. 
Therefore the second argument is (int a)=>a.ToString();
Therefore B is string.
Therefore the third parameter is Func<string, C>
Therefore the third argument is (string b)=>b.Length
Therefore C is int.
And we're done.

看到，我们需要A来制定B和B来解决C.在你的情况下想要从...中找出T，而你不能这样做。

See, we need A to work out B, and B to work out C. In your case you want to work out T from... T. And you can't do that.

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