对Java Builder类进行子类化 [英] Subclassing a Java Builder class

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本文介绍了对Java Builder类进行子类化的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

给予 Dobbs博士文章,特别是Builder模式,我们如何处理子类化Builder的情况?以我们要子类添加GMO标签的示例的缩小版本,一个天真的实现将是:

Give this Dr Dobbs article, and the Builder Pattern in particular, how do we handle the case of subclassing a Builder? Taking a cut-down version of the example where we want to subclass to add GMO labelling, a naive implementation would be:

public class NutritionFacts {                                                                                                    

    private final int calories;                                                                                                  

    public static class Builder {                                                                                                
        private int calories = 0;                                                                                                

        public Builder() {}                                                                                                      

        public Builder calories(int val) { calories = val; return this; }                                                                                                                        

        public NutritionFacts build() { return new NutritionFacts(this); }                                                       
    }                                                                                                                            

    protected NutritionFacts(Builder builder) {                                                                                  
        calories = builder.calories;                                                                                             
    }                                                                                                                            
}

子类:

public class GMOFacts extends NutritionFacts {                                                                                   

    private final boolean hasGMO;                                                                                                

    public static class Builder extends NutritionFacts.Builder {                                                                 

        private boolean hasGMO = false;                                                                                          

        public Builder() {}                                                                                                      

        public Builder GMO(boolean val) { hasGMO = val; return this; }                                                           

        public GMOFacts build() { return new GMOFacts(this); }                                                                   
    }                                                                                                                            

    protected GMOFacts(Builder builder) {                                                                                        
        super(builder);                                                                                                          
        hasGMO = builder.hasGMO;                                                                                                 
    }                                                                                                                            
}

现在,我们可以这样编写代码: p>

Now, we can write code like this:

GMOFacts.Builder b = new GMOFacts.Builder();
b.GMO(true).calories(100);

但是,如果我们收到订单错误,它们都会失败:

But, if we get the order wrong, it all fails:

GMOFacts.Builder b = new GMOFacts.Builder();
b.calories(100).GMO(true);

问题当然是 NutritionFacts.Builder 返回一个 NutritionFacts.Builder ,而不是一个 GMOFacts.Builder ,那么我们如何解决这个问题呢?一个更好的模式使用?

The problem is of course that NutritionFacts.Builder returns a NutritionFacts.Builder, not a GMOFacts.Builder, so how do we solve this problem, or is there a better Pattern to use?

注意:这个答案类似的问题提供了我上面的课程;我的问题是关于确保构建器调用的顺序正确的问题。

Note: this answer to a similar question offers up the classes I have above; my question is regarding the problem of ensuring the builder calls are in the correct order.

推荐答案

可以使用泛型来解决它。我认为这被称为好奇重复的通用模式

You can solve it using generics. I think this is called the "Curiously recurring generic patterns"

使基类构建器方法的返回类型成为一个通用参数。

Make the return type of the base class builder methods a generic argument.

public class NutritionFacts {

    private final int calories;

    public static class Builder<T extends Builder> {

        private int calories = 0;

        public Builder() {}

        public T calories(int val) {
            calories = val;
            return (T) this;
        }

        public NutritionFacts build() { return new NutritionFacts(this); }
    }

    protected NutritionFacts(Builder builder) {
        calories = builder.calories;
    }
}

现在使用派生类构建器实例化基础构建器通用参数。

Now instantiate the base builder with the derived class builder as the generic argument.

public class GMOFacts extends NutritionFacts {

    private final boolean hasGMO;

    public static class Builder extends NutritionFacts.Builder<Builder> {

        private boolean hasGMO = false;

        public Builder() {}

        public Builder GMO(boolean val) {
            hasGMO = val;
            return this;
        }

        public GMOFacts build() { return new GMOFacts(this); }
    }

    protected GMOFacts(Builder builder) {
        super(builder);
        hasGMO = builder.hasGMO;
    }
}

这篇关于对Java Builder类进行子类化的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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