如何在django中获取用户IP地址? [英] How do I get user IP address in django?
本文介绍了如何在django中获取用户IP地址?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何在django中获取用户的IP?
我有这样的视图:
#从django.contrib.gis.utils创建您的视图
从django.template导入GeoIP
从django.shortcuts导入RequestContext
导入render_to_response
def home(request):
g = GeoIP()
client_ip = request.META ['REMOTE_ADDR']
lat,long = g.lat_lon(client_ip)
return render_to_response('home_page_tmp.html',locals())
但是我得到这个错误:
/ mypage /
中的KeyError REMOTE_ADDR'
请求方法:GET
请求URL:http://mywebsite.com/mypage/
Django版本:1.2.4
异常类型:KeyError
异常值:
'REMOTE_ADDR'
异常位置:/mysite/homepage/views.py在家里,第9行
Python可执行文件:/ usr / bin / python
Python版本:2.6.6
Python路径: ['/ mysite','/usr/local/lib/python2.6/dist-packages/flup-1.0.2-py2.6.egg','/usr/lib/python2.6','/ usr / lib / python2.6 / plat-linux2','/usr/lib/python2.6/lib-tk','/usr/lib/python2.6/lib-old','/usr/lib/python2.6 / lib-dynload','/usr/local/lib/python2.6/dist-packages','/usr/lib/python2.6/dist-packages','/usr/lib/pymodules/python2.6' ]
服务器时间:Sun,2011年1月2日20:42:50 -0600
解决方案
def get_client_ip(request):
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
如果x_forwarded_for:
ip = x_forwarded_for.split(',')[0]
else:
ip = request.META.get('REMOTE_ADDR')
return ip
确保您的反向代理(如果有)配置正确(例如
注意:以上使用第一个项目 X-Forwarded-For
,但您可能希望使用最后一个项目(例如,在Heroku的情况下:获取客户在Heroku上的真实IP地址)
然后将请求作为参数传递给它;
get_client_ip(request)
How do I get user's IP in django?
I have a view like this:
# Create your views
from django.contrib.gis.utils import GeoIP
from django.template import RequestContext
from django.shortcuts import render_to_response
def home(request):
g = GeoIP()
client_ip = request.META['REMOTE_ADDR']
lat,long = g.lat_lon(client_ip)
return render_to_response('home_page_tmp.html',locals())
But I get this error:
KeyError at /mypage/
'REMOTE_ADDR'
Request Method: GET
Request URL: http://mywebsite.com/mypage/
Django Version: 1.2.4
Exception Type: KeyError
Exception Value:
'REMOTE_ADDR'
Exception Location: /mysite/homepage/views.py in home, line 9
Python Executable: /usr/bin/python
Python Version: 2.6.6
Python Path: ['/mysite', '/usr/local/lib/python2.6/dist-packages/flup-1.0.2-py2.6.egg', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/local/lib/python2.6/dist-packages', '/usr/lib/python2.6/dist-packages', '/usr/lib/pymodules/python2.6']
Server time: Sun, 2 Jan 2011 20:42:50 -0600
解决方案
def get_client_ip(request):
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
if x_forwarded_for:
ip = x_forwarded_for.split(',')[0]
else:
ip = request.META.get('REMOTE_ADDR')
return ip
Make sure you have reverse proxy (if any) configured correctly (e.g. mod_rpaf
installed for Apache).
Note: the above uses the first item in X-Forwarded-For
, but you might want to use the last item (e.g., in the case of Heroku: Get client's real IP address on Heroku)
And then just pass the request as argument to it;
get_client_ip(request)
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