PHP - 将文件系统路径转换为URL [英] PHP - Convert File system path to URL

问题描述

我经常发现我的项目中有需要从文件系统和用户浏览器访问的文件。一个例子是上传照片。我需要访问文件系统上的文件，以便我可以使用GD来更改图像或移动它们。但是我的用户也需要能够从像 example.com/uploads/myphoto.jpg 这样的URL访问文件。

由于上传路径通常对应于我构建的功能，似乎大部分时间工作的URL。以这些路径为例：

文件系统
/var/www/example.com/uploads/myphoto.jpg

网址
http://example.com /uploads/myphoto.jpg

如果我有一个变量设置为 / var /www/example.com / 然后我可以从文件系统路径中减去它，然后用它作为图像的URL。

  / ** 
 *从文件/路径字符串中移除给定的文件系统路径。 
 *如果文件/路径不包含给定的路径 - 返回FALSE。 
 * @param字符串$文件
 * @param字符串$路径
 * @return混合
 * / 
函数remove_path（$ file，$ path = UPLOAD_PATH）{ 
 if（strpos（$ file，$ path）！== FALSE）{
 return substr（$ file，strlen（$ path））; 
} 
} 
 
 $ file = /var/www/example.com/uploads/myphoto.jpg; 
 
 print remove_path（$ file，/var/www/site.com/）; 
 //打印uploads / myphoto.jpg
  

有谁知道更好的方法来处理这个问题？

解决方案假设目录是 / path / to / root / document_root / user /文件和地址是 site.com/user/file

第一个函数

  $ path = $ _SERVER ['SERVER_NAME']显示当前文件的相对于万维网地址的名称。 ]。 $ _SERVER [ PHP_SELF]; 
  

会导致：

  site.com/user/file 
  

第二个函数剥离给定的

$ p $ $ $ $ $ $ path $ str_replace（$ _ SERVER ['DOCUMENT_ROOT']，''，$ path）

由于我在 / path / to / root / document_root / user / file ，我会得到

  / user / file 
  




I often find that I have files in my projects that need to be accessed from the file system as well as the users browser. One example is uploading photos. I need access to the files on the file system so that I can use GD to alter the images or move them around. But my users also need to be able to access the files from a URL like example.com/uploads/myphoto.jpg.

Because the upload path usually corresponds to the URL I made up a function that seems to work most of the time. Take these paths for example:

File System /var/www/example.com/uploads/myphoto.jpg

URL http://example.com/uploads/myphoto.jpg

If I had a variable set to something like /var/www/example.com/ then I could subtract it from the filesystem path and then use it as the URL to the image.

/**
 * Remove a given file system path from the file/path string.
 * If the file/path does not contain the given path - return FALSE.
 * @param   string  $file
 * @param   string  $path
 * @return  mixed
 */
function remove_path($file, $path = UPLOAD_PATH) {
    if(strpos($file, $path) !== FALSE) {
        return substr($file, strlen($path));
    }
}

$file = /var/www/example.com/uploads/myphoto.jpg;

print remove_path($file, /var/www/site.com/);
//prints "uploads/myphoto.jpg"

Does anyone know of a better way to handle this?

解决方案

Assume the directory is /path/to/root/document_root/user/file and the address is site.com/user/file

The first function I am showing will get the current file's name relative to the World Wide Web Address.

$path = $_SERVER['SERVER_NAME'] . $_SERVER['PHP_SELF'];

and would result in:

site.com/user/file

The second function strips the given path of the document root.

$path = str_replace($_SERVER['DOCUMENT_ROOT'], '', $path)

Given I passed in /path/to/root/document_root/user/file, I would get

/user/file

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