在angularjs应用程序中重复调用firebase的地方在哪里? [英] Where to put duplicate calls to firebase in angularjs app?
问题描述
https://www.firebase.com/docs/web/libraries/angular/api.html#angularfire-firebasearray
现在我有(在coffeescript中):
$ p $ app $ angular_module'EApp' ,['ui.router','firebase']
app.config($ stateProvider,$ urlRouterProvider) - >
$ stateProvider
.state'catalog',
url:'/ catalog'
templateUrl:'partials / catalog.html'
controller:' catalogCtrl'
.state'product',
url:'/ product /:id'
templateUrl:'partials / product.html'
控制器:'productCtrl'
$ urlRouterProvider.otherwise'catalog'
return
app.controller'catalogCtrl',($ scope,$ rootScope,$ firebase) - >
ref = new Firebase(https://my-url.firebaseIO.com/)
$ scope.products = $ firebase(ref)。$ asArray()
return
app.controller'productCtrl',($ scope,$ rootScope,$ stateParams,$ firebase) - >
ref = new Firebase(https://my-url.firebaseIO.com/)
$ scope.products = $ firebase(ref)。$ asArray()
return
是否有任何方法可以将2个控制器中的通用代码分解并设置个产品在
$ rootScope
(或类似的)级别,以便我可以做一个 _。find
in productCtrl
一旦产品已经被返回了?
$ $ $ $ $ $ $ $ app.constant('FBURL', https://my-url.firebaseio.com/);
app.factory('products',function($ firebase,FBURL){
var ref = new Firebase(FBURL);
var products = $ firebase(ref)。$ asArray() ;
返回产品;
}
而不是(或除了) $ firebase
:
app。控制器'catalogCtrl',($ scope,products) - >
$ scope.products =产品
返回
在我的战壕应用程序中,我使用这种方法来设置这个微不足道的服务包装 $ firebaseSimpleLogin
:
app.factory('$ firebaseAuth' ($ firebase,$ firebaseSimpleLogin,FBURL){
var auth = $ firebaseSimpleLogin(new Firebase(FBURL));
return auth;
});
取决于当前的URL /路由(simpli
app.factory('board',function($ firebase, $ firebaseAuth,FBURL,$ routeParams){
var ref = new Firebase(FBURL +boards /+ $ routeParams.boardId);
var cards = $ firebase(ref.child('cards'))。$ asArray();
return {
ref:ref,
id:$ routeParams.boardId,$ b $ cards:cards,
}
});
I need to get a set of products
from firebase in every controller, and it would be ideal if I don't have to make an API call every single time. What is the best way to achieve this with the angularfire library?
https://www.firebase.com/docs/web/libraries/angular/api.html#angularfire-firebasearray
Right now I have (in coffeescript):
app = angular.module 'EApp', ['ui.router', 'firebase']
app.config ($stateProvider, $urlRouterProvider) ->
$stateProvider
.state 'catalog',
url: '/catalog'
templateUrl: 'partials/catalog.html'
controller: 'catalogCtrl'
.state 'product',
url: '/product/:id'
templateUrl: 'partials/product.html'
controller: 'productCtrl'
$urlRouterProvider.otherwise 'catalog'
return
app.controller 'catalogCtrl', ($scope, $rootScope, $firebase) ->
ref = new Firebase("https://my-url.firebaseIO.com/")
$scope.products = $firebase(ref).$asArray()
return
app.controller 'productCtrl', ($scope, $rootScope, $stateParams, $firebase) ->
ref = new Firebase("https://my-url.firebaseIO.com/")
$scope.products = $firebase(ref).$asArray()
return
Is there any way to factor out the common code in the 2 controllers and set products
at the $rootScope
(or similar) level such that I can do a _.find
in productCtrl
once the products have been returned?
As @tymeJV says in his comment, I'd indeed set up a service for the array:
app.constant('FBURL', "https://my-url.firebaseio.com/");
app.factory('products', function($firebase, FBURL) {
var ref = new Firebase(FBURL);
var products = $firebase(ref).$asArray();
return products;
}
And then simply inject that into your controllers instead of (or in addition to) $firebase
:
app.controller 'catalogCtrl', ($scope, products) ->
$scope.products = products
return
In my trenches app I've used this approach to set up this trivial service wrapping $firebaseSimpleLogin
:
app.factory('$firebaseAuth', function($firebase, $firebaseSimpleLogin, FBURL) {
var auth = $firebaseSimpleLogin(new Firebase(FBURL));
return auth;
});
And a somewhat less trivial service that depends on the current URL/route (simplified snippet below, "full" code is on github):
app.factory('board', function($firebase, $firebaseAuth, FBURL, $routeParams) {
var ref = new Firebase(FBURL+"boards/"+$routeParams.boardId);
var cards = $firebase(ref.child('cards')).$asArray();
return {
ref: ref,
id: $routeParams.boardId,
cards: cards,
}
});
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