Python数组乘法 [英] Python array multiply

问题描述

  hh = [[82.5]，[168.5]] 
 N = 1. / 5 
 ll = N * hh 
  

我做错了什么？我收到错误：
$ b

无法乘以$ b $的非int类型的序列'float'

我尝试添加float（），但这不能解决我的问题;

我需要乘以数组中的每个元素...
感谢所有

---

为数组*，但如何乘数组数组，我试着相同的数组*，但有问题：

编辑2：**

  hh = [[82.5]，[168.5]] 
 N = zip（* hh）
 ll = [[x * N for x in y] for y in hh] 
  

???

解决方案

当你在Python中乘以 X 时，它不会乘以序列 - 它所做的是重复序列 X 次。这就是为什么X必须是一个整数（它不能是一个浮点数）。

你想要做的是使用列表理解：

  hh = [[82.5]，[168.5]] 
 N = 1.0 / 5 
 ll = [[x * N for x in y] for y in hh] 
  

hh=[[82.5], [168.5]]
N=1./5
ll=N*hh

What I'm doing wrong? I received error :

"can't multiply sequence by non-int of type 'float'"

I try to add float(), but this is not solve my problem;

I need to multiply each element in array... thanks to all

---

**Ok thanks for idea for number * array, but how to multiply array*array, I tried same as number*array, but have problems:

EDIT 2:**

hh=[[82.5], [168.5]]
N=zip(*hh)
ll = [[x*N for x in y] for y in hh]

???

解决方案

When you multiply a sequence by X in Python, it doesn't multiply each member of the sequence - what it does is to repeat the sequence X times. That's why X has to be an integer (it can't be a float).

What you want to do is to use a list comprehension:

hh = [[82.5], [168.5]]
N  = 1.0 / 5
ll = [[x*N for x in y] for y in hh]

这篇关于Python数组乘法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！