Go,Golang,formatFloat:将浮点数转换为字符串 [英] Go, Golang, formatFloat : convert float number to string
问题描述
http://golang.org/pkg/strconv/
http://play.golang.org/p/4VNRgW8WoB
如何将浮点数转换为字符串格式?
这是谷歌游乐场,但没有得到预期的输出。 (2e + 07)
我想得到21312421.213123
包主
importfmt
importstrconv
func floattostr(input_num float64)string {
//将浮点数转换为字符串
返回strconv.FormatFloat(input_num,'g',1,64)
}
func main(){
fmt.Println(floattostr(21312421.213123))
//我期望的是字符串格式的21312421.213123
}
请帮我搞定该字符串不在浮点数中。谢谢
package main
importfmt
importstrconv
func FloatToString(input_num float64)string {
//将浮点数转换为字符串
返回strconv.FormatFloat(input_num,'f',6,64)
$ b func main(){
fmt.Println(FloatToString(21312421.213123))
}
如果您只想要尽可能多的数字精度,那么特殊精度-1使用必需的最小数字位数,以便ParseFloat将精确返回f。例如
strconv.FormatFloat(input_num,'f',-1,64)
我个人觉得 fmt
更易于使用。 ( Playground链接)
fmt.Printf(x =%.6f\\\
,21312421.213123)
或者if你只是想转换字符串
pre $ $ $ $ $ $ $ $ $ $ $ $ $ code>
http://golang.org/pkg/strconv/
http://play.golang.org/p/4VNRgW8WoB
How do I convert a float number into string format? This is google playground but not getting the expected output. (2e+07) I want to get "21312421.213123"
package main
import "fmt"
import "strconv"
func floattostr(input_num float64) string {
// to convert a float number to a string
return strconv.FormatFloat(input_num, 'g', 1, 64)
}
func main() {
fmt.Println(floattostr(21312421.213123))
// what I expect is "21312421.213123" in string format
}
Please help me get the string out of float number. Thanks
package main
import "fmt"
import "strconv"
func FloatToString(input_num float64) string {
// to convert a float number to a string
return strconv.FormatFloat(input_num, 'f', 6, 64)
}
func main() {
fmt.Println(FloatToString(21312421.213123))
}
If you just want as many digits precision as possible, then the special precision -1 uses the smallest number of digits necessary such that ParseFloat will return f exactly. Eg
strconv.FormatFloat(input_num, 'f', -1, 64)
Personally I find fmt
easier to use. (Playground link)
fmt.Printf("x = %.6f\n", 21312421.213123)
Or if you just want to convert the string
fmt.Sprintf("%.6f", 21312421.213123)
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