无法将java.lang.Integer字段设置为java.lang.Integer [英] Can not set java.lang.Integer field to java.lang.Integer

问题描述

用户声明：

  @Entity 
 public class User {
 @Id 
 @GeneratedValue 
私人整数ID; 
 .... 
  

模式声明：

  @Entity 
公共类模式{
 @Id 
 @GeneratedValue 
整数ID; 
 ... 
  

UserPatternDeclaration：

  public class UserPattern {
 @Id 
 @GeneratedValue 
 Integer id; 
 
 @ManyToOne 
 @JoinColumn（name =user_id）
用户用户; 
 
 @ManyToOne 
 @JoinColumn（name =pattern_id）
模式模式; 
 ... 
  

请求数据库：

  Session session = sessionFactory.getCurrentSession（）; 
 Query query = session.createQuery（from UserPattern where user =：user_id and pattern =：pattern_id）; 
 query.setParameter（user_id，userId）; 
 query.setParameter（pattern_id，pattern_id）; 
列表< UserPattern> list = query.list（）; //异常在这里抛出
  

我有下面的异常：

  ... 
 java.lang.IllegalArgumentException异常：不能设置为java.lang.Integer场
 COM .. ... s.model.User.id to java.lang.Integer 
 at sun.reflect.UnsafeFieldAccessorImpl.throwSetIllegalArgumentException（UnsafeFieldAccessorImpl.java:164）
 at sun.reflect.UnsafeFieldAccessorImpl.throwSetIllegalArgumentException（UnsafeFieldAccessorImpl。 Java的：在sun.reflect.UnsafeFieldAccessorImpl.ensureObj（UnsafeFieldAccessorImpl.java:55 168）
）
在sun.reflect.UnsafeObjectFieldAccessorImpl.get（UnsafeObjectFieldAccessorImpl.java:36）
在java.lang中.reflect.Field.get（Field.java:379）
 .... 
  

我已阅读相关主题< a href =https://stackoverflow.com/questions/6693950/点击，但我没有找到答案。

PS

hibernate日志（在异常之前）：

  Hibernate：
 select 
 userpatter0_.id为id1_2_，
 userpatter0_.amountSearched为amountSe2_2_，
 userpatter0_.amountplayed为amountpl3_2_，
 userpatter0_.pattern_id为pattern_4_2_，
 userpatter0_.user_id为user_id5_2_ 
 from 
 UserPattern userpatter0_ 
其中
 userpatter0_.user_id =？ 
和userpatter0_.pattern_id =？ 
  

在浏览器中，我看到以下消息：

  HTTP Status 500 ....无法通过... model.User.id的反射getter获取字段值
  

解决方案

如果您将您的HQL查询从UserPattern更改为，那么user.id =：user_id和pattern .id =：pattern_id ？

我认为Hibernate会令对象和ID字段混淆。

User declaration:

@Entity
public class User {
    @Id
    @GeneratedValue
    private Integer id;
    ....

Pattern declaration:

@Entity
public class Pattern {
    @Id
    @GeneratedValue
    Integer id;
    ...

UserPatternDeclaration:

public class UserPattern {
    @Id
    @GeneratedValue
    Integer id;

    @ManyToOne
    @JoinColumn(name = "user_id")
    User user;

    @ManyToOne
    @JoinColumn(name = "pattern_id")
    Pattern pattern;
    ...

request to database:

Session session = sessionFactory.getCurrentSession();
Query query = session.createQuery("from UserPattern where user = :user_id and pattern = :pattern_id ");
query.setParameter("user_id", userId);
query.setParameter("pattern_id", pattern_id);
List<UserPattern> list = query.list();//exception throws here

I got following exception:

 ...
    java.lang.IllegalArgumentException: Can not set java.lang.Integer field 
    com.....s.model.User.id to java.lang.Integer
        at sun.reflect.UnsafeFieldAccessorImpl.throwSetIllegalArgumentException(UnsafeFieldAccessorImpl.java:164)
        at sun.reflect.UnsafeFieldAccessorImpl.throwSetIllegalArgumentException(UnsafeFieldAccessorImpl.java:168)
        at sun.reflect.UnsafeFieldAccessorImpl.ensureObj(UnsafeFieldAccessorImpl.java:55)
        at sun.reflect.UnsafeObjectFieldAccessorImpl.get(UnsafeObjectFieldAccessorImpl.java:36)
        at java.lang.reflect.Field.get(Field.java:379)
    ....

Please help to fix this issue.

error message looks very very strange.

I have read related topic click but I don't found out answer.

P.S.

hibernate log(before exception):

Hibernate: 
    select
        userpatter0_.id as id1_2_,
        userpatter0_.amountSearched as amountSe2_2_,
        userpatter0_.amountplayed as amountpl3_2_,
        userpatter0_.pattern_id as pattern_4_2_,
        userpatter0_.user_id as user_id5_2_ 
    from
        UserPattern userpatter0_ 
    where
        userpatter0_.user_id=? 
        and userpatter0_.pattern_id=?

In browser I see following message:

HTTP Status 500....could not get a field value by reflection getter of...model.User.id

解决方案

What happens if you change your HQL query to from UserPattern where user.id = :user_id and pattern.id = :pattern_id?

I think Hibernate is confusing objects and ID fields.

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