jQuery如何将div包装在多个相同的类元素中 [英] jQuery How to wrap div around multiple of the same class elements
问题描述
我试图将多个相同的类div包装到div中,并跳过不具有相同类的div。 .wrap不会合并它们,并且.wrapAll会在下面引发非分类的div。我一直在试图创建一个替代解决方案,但没有用。
原始
< div class =entry>内容< / div>
< div class =entry>内容< / div>
< div class =entry>内容< / div>
< div>跳过换行< / div>
< div class =entry>内容< / div>
< div class =entry>内容< / div>
< div class =entry>内容< / div>
续...
通缉结果
< div>
< div class =entry>内容< / div>
< div class =entry>内容< / div>
< div class =entry>内容< / div>
< / div>
< div>跳过换行< / div>
< div>
< div class =entry>内容< / div>
< div class =entry>内容< / div>
< div class =entry>内容< / div>
< / div>
c>< div> 元素使用作为
循环。在下面的代码中,只需在这里改变初始选择器来获取所有的兄弟div,例如 #content> div.entry
或无论它们在哪里:
var divs = $(div.entry) ; $(&);
for(var i = 0; i i + = divs.eq(i).nextUntil(':not(.entry)')。andSelf()。wrapAll '< div />').length;
}
你可以在这里试试看。我们只是循环使用 .entry
< div>
元素,使用 .nextUntil()
获取所有 .entry
元素,直到使用 .entry rel =noreferrer> :not()
选择器。然后,我们将采用下一个元素,加上我们开始的元素( .andSelf()
)并执行 .wrapAll()
。在它们被包装后,我们正在跳过循环中的许多元素。
I'm trying to wrap multiple same class divs into a div and to skip divs not with the same class. .wrap doesn't combine them, and .wrapAll throws the non-classed divs underneath. I've been tinkering around with attempts to create an alternate solution but with no avail.
Original
<div class="entry">Content</div>
<div class="entry">Content</div>
<div class="entry">Content</div>
<div>Skip in wrap</div>
<div class="entry">Content</div>
<div class="entry">Content</div>
<div class="entry">Content</div>
continued...
Wanted Result
<div>
<div class="entry">Content</div>
<div class="entry">Content</div>
<div class="entry">Content</div>
</div>
<div>Skip in wrap</div>
<div>
<div class="entry">Content</div>
<div class="entry">Content</div>
<div class="entry">Content</div>
</div>
You can loop pretty quickly through your <div>
elements using a for
loop. In the below code, just change the initial selector here to grab all those siblings divs, e.g. #content > div.entry
or wherever they are:
var divs = $("div.entry");
for(var i=0; i<divs.length;) {
i += divs.eq(i).nextUntil(':not(.entry)').andSelf().wrapAll('<div />').length;
}
You can give it a try here. We're just looping through, the .entry
<div>
elements using .nextUntil()
to get all the .entry
elements until there is a non-.entry
one using the :not()
selector. Then we're taking those next elements, plus the one we started with (.andSelf()
) and doing a .wrapAll()
on that group. After they're wrapped, we're skipping ahead either that many elements in the loop.
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