简单的raw_input和条件 [英] Simple raw_input and conditions

问题描述

我创建了简单的代码：

name = raw_input("Hi. What's your name? \nType name: ")
age = raw_input("How old are you " + name + "? \nType age: ")

if age >= 21
    print "Margaritas for everyone!!!"
else:
    print "NO alcohol for you, young one!!!"

raw_input("\nPress enter to exit.")

It工作得很好，直到我得到'if'语句...它告诉我，我使用的语法无效。

It works great until I get to the 'if' statement... it tells me that I am using invalid syntax.

我正在努力学习如何使用Python，并且已经对代码进行了大量的讨论，但我无法弄清楚我做错了什么（可能是非常基本的。

I am trying to learn how to use Python, and have messed around with the code quite a bit, but I can't figure out what I did wrong (probably something very basic).

推荐答案

它应该是这样的：

name = raw_input("Hi. What's your name? \nType name: ")
age = raw_input("How old are you " + name + "? \nType age: ")
age = int(age)

if age >= 21:
    print "Margaritas for everyone!!!"
else:
    print "NO alcohol for you, young one!!!"

raw_input("\nPress enter to exit.")

你错过了冒号。此外，你应该将年龄从字符串转换为int。

You were missing the colon. Also, you should cast age from string to int.

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