C ++包括完整路径 [英] C++ include with full path

问题描述

我发现 #include../ app / thing.h非常难看，我希望能够从我项目的主根导入，比如这个：

I find #include "../app/thing.h" very ugly and I would like to be able to import from the main root of my project, like this:

#include< project / app / submodule / thing.h>

（我知道<>通常用于外部，但我觉得它更干净）

(I know <> is generally used for external but I find it very cleaner)

我怎么能在任何地方都这样做在我的项目中？

How can I do that, from anywhere in my project?

推荐答案

您只需确保构建过程设置一个选项以指定搜索的起始点。

You simply need to ensure that your build process sets an option to specify the starting point of the search.

例如，如果您的标题位于：

For example, if your header is in:

/work/username/src/project/app/submodule/thing.h

然后你需要包括（假设符合POSIX的编译器; AFAICR，甚至MSVC使用 / I 作为 -I 的类似物：

then you need to include (assuming a POSIX-compliant compiler; AFAICR, even MSVC uses /I as the analogue of -I):

-I/work/username/src

作为编译器选项之一。您可以从项目的任何位置使用该路径，因为它是绝对的。你只需要一个定义的方式让你的构建系统知道设置应该是什么，所以当它被移动到 / home / someone / src / 时，你只有一个设置改变。

as one of the compiler options. You can use that path from anywhere in your project since it is absolute. You just need a defined way for your build system to know what the setting should be, so that when it is moved to /home/someone/src/, you have only one setting to change.

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